Answer:
the probability that five randomly selected students will have a mean score that is greater than the mean achieved by the students = 0.0096
Step-by-step explanation:
From the five randomly selected students ; 160, 175, 163, 149, 153
mean average of the students = 160+175+163+149+153/5
= mean = x-bar = 800/5
mean x-bar = 160
from probability distribution, P(x-bar > 160) = P[ x-bar - miu / SD > 160 -150.8 /3.94]
P( Z>2.34) = from normal Z-distribution table
= 0.0096419
= 0.0096
hence the probability that five randomly selected students will have a mean score that is greater than the mean achieved by the students = 0.0096
where SD = standard deviation = 3.94 and Miu = 150.8
Answer:
? is there a option?
Step-by-step explanation:
Answer:
It has a slope of 1.
Step-by-step explanation:
First, you need to choose two points. The points HAS to be exactly on top of the line.
The two points I picked where
(-2,0) and (-1,1)
All you do is subtract the two points. Remember rise over run or y/x
1 -0 = 1
-1 - (-2) = 1
