Area of a circle = 3.14 x r^2
=3.14 x 8.5^2
= 226.865
So lets try to prove it,
So let's consider the function f(x) = x^2.
Since f(x) is a polynomial, then it is continuous on the interval (- infinity, + infinity).
Using the Intermediate Value Theorem,
it would be enough to show that at some point a f(x) is less than 2 and at some point b f(x) is greater than 2. For example, let a = 0 and b = 3.
Therefore, f(0) = 0, which is less than 2, and f(3) = 9, which is greater than 2. Applying IVT to f(x) = x^2 on the interval [0,3}.
Learn more about Intermediate Value Theorem on:
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2.5 bc JL is 5 that's the whole bottom of the triangle and ML is from center to right and vice versa.
X+3y=14
-x. -x
3y=-x+14
Divide them all by 3
Y=-x/3+14/3
Y-intercept= 1/3
Answer:
Step-by-step explanation:
