When dividing 250,000 by 100, the digits in the quotient move how many places to the right?
1 answer:
When dividing 250,000 by 100, the digits in the quotient move by 2 places to the right.
<u>Step-by-Step explanation:</u>
Here we have , to find out that When dividing 250,000 by 100, the digits in the quotient move how many places to the right . Let's find out:
⇒ dividing 250,000 by 100
⇒ 250,000 / 100
⇒
⇒
⇒
Initially we had 250,000 of 6 digits and now after dividing 250,000 by 100, we have 2500 of 4 digits ! So , Number of places quotient shift to right is:
⇒
⇒
Therefore, When dividing 250,000 by 100, the digits in the quotient move by 2 places to the right.
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Firstly, subtract 3x on both sides of the equation:
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Now looking at this equation, we see that the slope is 3/4. Now since our new line is perpendicular, this means that <em>its slope is -4/3.</em>
Now that we have the slope, plug that into the m variable and plug in (-4,-5) into the x and y coordinates to solve for the b variable as such:
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Answer:
2
Step-by-step explanation:
The question state that; the sum of a number, 1/6 of that number, 2 1/2 of that number, and 7 is 12 1/2. Find the number.
First, we need to interpret and represent this statement mathematically
Let n be the number.
The sum means 'addition'
1/6 of that number is 1/6 of n = 1/6 × n =
2 1/2 of that number is 2 1/2 of n = 2 1/2 × n = 5/2 × n =
So the question says that, when we add; ,
and 7 all together, the value is 12 1/2
That is;
+
+ 7 = 12 1/2
+
+ 7 =
( changing 12 1/2 to improper fraction will give
)
So we can now go ahead and solve for n
+
+ 7 =
subtract 7 from both-side of the equation
+
=
- 7
=
=
can be reduced to give us
=
Cross multiply
8n × 2 = 11× 3
16n = 33
Divide both-side of the equation by 16
=
(On the left-hand side of the equation, 16 will cancel-out 16 leaving us with just, while on the right-hand side of the equation 33 will be divided by 16)
n = =
Therefore the number is