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bazaltina [42]
3 years ago
10

Determine the amount of money you need to invest to have $18,000 dollars in 2 years if you Invest it at 20% annual Interest, com

pounded
continuously.
$28,852.84
$17,294.21
$12,065.76
$133,033.01
Mathematics
1 answer:
vekshin13 years ago
3 0

Answer:

$12,500

Step-by-step explanation:

Using the compound interest formula Accrued Amount = P (1 + r)^n

where Accrued amount = $18000

P = principal; we need to generate it

r = 20% = 0.2

n = 2

Therefore

P = Accrued amount/ (1 + r)^n

= 18000/(1+0.2)^2

= 18000/1.44

= 12,500

hence $12,500 needs to be invested

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Find the radius of a circle that has an area of 6.76 cm². Use it for pi.
Inessa05 [86]

Answer:

<h2>radius = 1.47 cm</h2>

Step-by-step explanation:

Area of a circle = πr²

where

r is the radius

From the question

Area = 6.76 cm²

To find the radius substitute the value of the area into the above formula and solve for the radius

That's

6.76 = \pi \:  {r}^{2}

Divide both sides by π

We have

{r}^{2}  =  \frac{6.76}{\pi}  \\ r =  \sqrt{ \frac{6.76}{\pi} }

r = 1.46689291

We have the final answer as

radius = 1.47 cm

Hope this helps you

8 0
3 years ago
100p for an answer please
Rainbow [258]
So from solving the problem, we know that the answer must equal -28.

When you solve all of the given options, we find that the only one that does equal -28 would be A.) (-6)(4) + (-6)(2/3).

When I doubt, solve it out. I hope I could help!
7 0
3 years ago
Step 1 of 3: Each year a nationally recognized publication conducts its Survey of America’s Best Graduate and Professional Schoo
lukranit [14]

Answer:

Step-by-step explanation:

Hello!

Given the variables

Y: Starting salary of a graduate at a top business school

X: GMAT score of the business school

The sample used had a size n=20

The estimated regression equation was ^Y= -92040 + 228Xi

The correlation coefficients were r= 0.81

You need to know if r is statistically significant at a 0.05 level:

Assuming the hypotheses are:

H₀: There is a linear correlation between the variables of interest

H₁: There is no linear correlation between the variables of interest

α: 0.05

This test is two-tailed.

The p-value for a r=0.81 and n=20 is 0.000015

Using the p-value approach, the decision rule is:

If p-value ≤ α, reject the null hypothesis

If p-value > α, do not reject the null hypothesis

In this case, the p-value is less than α, the decision is to reject the null hypothesis.

At a 5% level, you can conclude that the coefficient of correlation is statistically significant.

4 0
3 years ago
Jackson recorded the growth of a plant over 10 weeks. The equation y=0.25+4 represents the height y in inches over time x in wee
Naya [18.7K]

Answer:

Step-by-step explanation:

Allow me to rewrite your question and hope it will fit the original one:

<em>Jackson recorded the growth of a plant over 10 weeks. The equation </em><em>y=0.25x+4</em><em> represents the height y in inches over time x in weeks what does the y intercept represent In terms of the situation</em>

My answer:

As we know that y intercept is the value of y at the point where the line crosses the y axis (the value of x =0)

So in this situation, if x= 0, it means the height of the tree (y-intercept) initially be at 4 at week 0.

Hope it will find you well.

5 0
3 years ago
The population of a colony of mosquitoes obeys the law of uninhibited growth. If there are 1000 mosquitoes initially and there a
Anettt [7]

Answer:

1) The size of the colony after 4 ​days is 6553 mosquitoes

2) After t = 4.9\ days

Step-by-step explanation:

To answer this question you must use the growth formula

N = N_0e ^ {kt}

Where

N_0 is the initial population of mosquitoes = 1000

t is the time in days

k is the growth rate

N is the population according to the number of days

We know that when t = 1 and N_0=1000 then N = 1600

Then we use these values to find k.

1600 = 1000e ^{k(1)}\\\\\frac{1600}{1000} = e ^ k\\\\ln(\frac{1600}{1000}) = k\\\\k = 0.47

Now that we know k we can find the size of the colony after 4 days.

N = 1000e ^ {0.47(4)}\\\\N = 6553\ mosquitoes

To know how long it should take for the population to reach 10,000 mosquitoes we must do N = 10000 and solve for t.

10000 = 1000e ^ {0.47t}\\\\10 = e ^ {0.47t}\\\\ln(10) = 0.47t\\\\t = \frac{ln(10)}{0.47}\\\\t = 4.9\ days

6 0
3 years ago
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