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Stells [14]
3 years ago
13

Which postulate can be used to prove that the two triangles below are Congruent?

Mathematics
2 answers:
Eddi Din [679]3 years ago
8 0
A
angle vtu is congruent to rts and the rest is given
maks197457 [2]3 years ago
5 0

Answer:

B. SAA (Side-Angle-Angle)

Step-by-step explanation:

In the diagram given, the horizontal sides of the two triangles are equal. Also, by the principle of opposite angles,

                   < RTS = < QTV

The two angles are equal.

Furthermore, the sum of angles in a triangle is 180^{0}, so the third angle can be determined since

                  < RST = < VQT = 90^{0}

Thus the two triangles are congruent due to side - angle- angle.

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Triangle ABC and DEF are right triangles, as shown. Triangle ABC is similar to triangle DEF. which ratios are equal to sin C?
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First option and Fourth option.

Step-by-step explanation:

To solve this exercise you need to use the following Trigonometric Identity:

sin\alpha=\frac{opposite}{hypotenuse}

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Since triangle ABC is similar to triangle DEF:

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Let's begin with the triangle ABC.

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opposite=AB\\hypotenuse=AC

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Lindsay is checking out books at the library, and she is primarily interested in mysteries and nonfiction. She has narrowed her
Ratling [72]

Answer:

0.0677 = 6.77% probability that they will all be nonfiction

Step-by-step explanation:

The books are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

10 + 12 = 22 books.

She chooses 4 books, which means that n = 4

12 nonfiction, which meas that k = 12

What’s the probability that they will all be nonfiction?

This is P(X = 4). So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 4) = h(4,22,4,12) = \frac{C_{12,4}*C_{10,0}}{C_{22,4}} = 0.0677

0.0677 = 6.77% probability that they will all be nonfiction

7 0
3 years ago
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