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Stells [14]
3 years ago
13

Which postulate can be used to prove that the two triangles below are Congruent?

Mathematics
2 answers:
Eddi Din [679]3 years ago
8 0
A
angle vtu is congruent to rts and the rest is given
maks197457 [2]3 years ago
5 0

Answer:

B. SAA (Side-Angle-Angle)

Step-by-step explanation:

In the diagram given, the horizontal sides of the two triangles are equal. Also, by the principle of opposite angles,

                   < RTS = < QTV

The two angles are equal.

Furthermore, the sum of angles in a triangle is 180^{0}, so the third angle can be determined since

                  < RST = < VQT = 90^{0}

Thus the two triangles are congruent due to side - angle- angle.

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1 2 4 and 5 please hurry
GREYUIT [131]

Answer:

1 is 0.6 and 2 is 612 3 is 39.2 and 4 is -3 and 5 is 9/4 or (2 1/4)

Step-by-step explanation:

:)

8 0
2 years ago
Determine if they are similar, congruent or neither
Leona [35]
They are congruent.
5 0
3 years ago
Find a point-slope form for the line that satisfies the stated conditions.
Yakvenalex [24]

Answer:

y=6x+41

Step-by-step explanation:

y-5=6(x+6)

y=6x+41

3 0
3 years ago
A cubical box without a top is 4 cm on each edge.it contains 64 identical 1cm cubes that exactly fill the box. How many of these
Len [333]

Answer:

52

Step-by-step explanation:

A cubical box without a top is 4 cm on each edge containing 64 identical 1 cm cubes.

We have to find the number of small cubes that actually touch the box.

Now, there are 4 layers of 16 cubes from bottom to top.

In the bottom-most layer, all the 16 small cubes will touch the bottom of the large cube.

Again, from the top three layers, only the outer small cubes will touch the sides of the large cube.

So, there are 12 small cubes in each top three layers that will touch the large cube.

Hence, in total there will be (16 + 12 ×3) = 52 small cubes that actually touch the large cube box. (Answer)

8 0
3 years ago
Please help asap! Tysm! I will give brainliest and thanks. :)
dsp73

Answer:

(-2,4)

Step-by-step explanation:

There are multiple answers for this, basically anything with an x-value of: -4, -2, 0, 2, or 4

So, you could have (2,4) , (-4,3) , (0,17), (2, -5), etc.

This is because, to be a function, each x-value can only have one corresponding y-value.  Thus, by giving the x-values (in this case, again, -4,-2,0,2, or 4) another y-value, the relation will not be a function.  

Easy answer: An x-value can only have one y-value

8 0
3 years ago
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