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swat32
3 years ago
5

How do you know that a sealed calorimeter is a closed system? Because the temperature is conserved Because the masses of the sam

ple and water are equal Because the thermal energy is not transferred to the environment Because the work is done on the test sample
Physics
2 answers:
pickupchik [31]3 years ago
7 0

Answer:C. Because thermal energy has not transferred to the environment.

Explanation:

Anuta_ua [19.1K]3 years ago
3 0

Answer: A sealed calorimeter is a closed system because thermal energy is not transferred to the environment.


A closed system is an isolated system where there is no transfer of energy with its surroundings. Also the system is not subjected to any external force whose source is external to the system.



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Can a body move with a certain velocity in the direction of the east have acceleration in the direction of the west?
levacccp [35]
Answer:
Yes, a body with a certain velocity can have an opposite acceleration, the acceleration would then be negative, since it is opposite to the direction to the velocity and also because the direction in which the acceleration is portrayed is on the left-hand side.

Hope this answer helps :)
7 0
4 years ago
Which event is an example of condensation?
Sonbull [250]

Answer:

Fog forms in a valley

Explanation: that’s the only reasonable response

5 0
4 years ago
Convert 6.8 gallons into liters
poizon [28]
25.7408 liters. There are 3.78541 liters in one gallon
4 0
4 years ago
The Great Sandini is a 60 kg circus performer who is shotfrom a cannon (actually a spring gun). You don't find many men ofhis ca
d1i1m1o1n [39]

Answer:

V=15.3 m/s

Explanation:

To solve this problem, we have to use the energy conservation theorem:

U_e+K_i+U_{gi}+W_{friction}=K_f+U_{gf}

the elastic potencial energy is given by:

U_e=\frac{1}{2}*k*x^2\\U_e=\frac{1}{2}*1100N/m*(4m)^2\\U_e=8800J

The work is defined as:

W_{friction}=F_f*d*cos(\theta)\\W_{friction}=40N*2.5m*cos(180)\\W_{friction}=-100J

this work is negative because is opposite to the movement.

The gravitational potencial energy at 2.5 m aboves is given by:

U_{gf}=m*g*h\\U_{gf}=60kg*9.8*2.5\\U_{gf}=1470J

the gravitational potential energy at the ground and the kinetic energy at the begining are 0.

8800J+0+0+-100J=\frac{1}{2}*62kg*v^2+1470J\\v=\sqrt{\frac{2(8800J-100J-1470J)}{62kg}}\\v=15.3m/s

3 0
3 years ago
Suppose a convex mirror has a focal length of 120 cm. A candle sits directly in front of the mirror. If the image of that candle
Andru [333]
We can solve the problem by using the mirror equation:
\frac{1}{f} = \frac{1}{d_o}+ \frac{1}{d_i}
where
f is the focal length
d_o is the distance of the object from the mirror
d_i is the distance of the image from the mirror

For the sign convention, the focal length is taken as negative for a convex mirror:
f=-120 cm
and the image is behind the mirror, so virtual, therefore its sign is negative as well:
d_i=-24 cm
putting the numbers in the mirror equation, we find the distance of the object from the mirror surface:
\frac{1}{d_o} = \frac{1}{f}- \frac{1}{d_i}= \frac{1}{-120 cm} - \frac{1}{-24 cm}= \frac{1}{30 cm}
So, the distance of the object from the mirror is d_o = 30 cm
8 0
4 years ago
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