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Mekhanik [1.2K]
3 years ago
7

The Great Sandini is a 60 kg circus performer who is shotfrom a cannon (actually a spring gun). You don't find many men ofhis ca

liber, so you help him design a new gun. This new gun has avery large spring with a very small mass and a force constant of1100 N/m that he will compress with a force of4400 N. The inside of the gun barrel is coated with Teflon, sothe average friction force will be only 40 N during the 4.0 m he moves in the barrel.
At what speed will he emerge from the end of the barrel, 2.5 mabove his initial rest position?
Physics
1 answer:
d1i1m1o1n [39]3 years ago
3 0

Answer:

V=15.3 m/s

Explanation:

To solve this problem, we have to use the energy conservation theorem:

U_e+K_i+U_{gi}+W_{friction}=K_f+U_{gf}

the elastic potencial energy is given by:

U_e=\frac{1}{2}*k*x^2\\U_e=\frac{1}{2}*1100N/m*(4m)^2\\U_e=8800J

The work is defined as:

W_{friction}=F_f*d*cos(\theta)\\W_{friction}=40N*2.5m*cos(180)\\W_{friction}=-100J

this work is negative because is opposite to the movement.

The gravitational potencial energy at 2.5 m aboves is given by:

U_{gf}=m*g*h\\U_{gf}=60kg*9.8*2.5\\U_{gf}=1470J

the gravitational potential energy at the ground and the kinetic energy at the begining are 0.

8800J+0+0+-100J=\frac{1}{2}*62kg*v^2+1470J\\v=\sqrt{\frac{2(8800J-100J-1470J)}{62kg}}\\v=15.3m/s

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According to the principle of the conservation of linear momentum, the momentum before collision is equal to the total momentum after collision.

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2 years ago
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Answer:

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