A. similar animals fossils found in South America and Africa
Hope this helps :)
Suppose that the proportion of the white crest alleles (r) is given by w and that of the Red crest allele (R) is given by p. We have that p+w=1. The probability that an individual has 2 r alleles is given by w*w since for each allele position the probability is w. Only these individuals have a White phenotype. Hence, we get that w^2=

; the right hand side is the proportion of white birds in the total population. Doing the calculations, this yields that w=0.37. From this, we calculate that p=0.63. The possible ways we have heterozygous individuals are the combinations Rr and rR. The probability for each of those is p*w. Thus, the total probability is 2pw. This is equal to 0.466=0.47. This is the fraction of the future population that is going to be heterozygous assuming the conditions of the Handy-Weinberg equilibrium like random reproductive matching etc.
<span>prophase I. the chromosomes condense, and the nuclear envelope breaks down. ...Metaphase I. pairs of homologous chromosomes move to the equator of the cell.Anaphase I. homologous chromosomes move to opposite poles of the cell.Telophase I and Cytokinesis. ...Prophase II. ...Metaphase II. ...Anaphase II. ...<span>Telophase II and Cytokinesis.</span></span>
The correct answer is - 5:35 PM on Friday.
The low tides, as well as the high tides, occur two times in a lunar day, on exactly every half a lunar day passed. A lunar day is 24 hours and 50 minutes long, so every next low tide, or high tide, appears after 12 hours and 25 minutes after the previous one. In this situation we have a low tide that has appeared at 5:10 AM on Friday, so in order to calculate when the other low tide will appear we need to add 12 hours and 25 minutes on it, and that will gives the information that the next low tide will appear at 5:35 PM on Friday.