![\\ \tt\leadsto \dfrac{d[NH_3]}{dt}=1.50\times 10^{-6}](https://tex.z-dn.net/?f=%5C%5C%20%5Ctt%5Cleadsto%20%5Cdfrac%7Bd%5BNH_3%5D%7D%7Bdt%7D%3D1.50%5Ctimes%2010%5E%7B-6%7D)
- dt remains same for reaction
![\\ \tt\leadsto \dfrac{d[H_2]}{dt}=\dfrac{3}{2}\dfrac{d[NH_3]}{dt}](https://tex.z-dn.net/?f=%5C%5C%20%5Ctt%5Cleadsto%20%5Cdfrac%7Bd%5BH_2%5D%7D%7Bdt%7D%3D%5Cdfrac%7B3%7D%7B2%7D%5Cdfrac%7Bd%5BNH_3%5D%7D%7Bdt%7D)
![\\ \tt\leadsto \dfrac{d[H_2]}{dt}=\dfrac{3}{2}(1.5\times 10^{-6})](https://tex.z-dn.net/?f=%5C%5C%20%5Ctt%5Cleadsto%20%5Cdfrac%7Bd%5BH_2%5D%7D%7Bdt%7D%3D%5Cdfrac%7B3%7D%7B2%7D%281.5%5Ctimes%2010%5E%7B-6%7D%29)
![\\ \tt\leadsto \dfrac{d[H_2]}{dt}=2.25\times 10^{-6}Ms^{-1}](https://tex.z-dn.net/?f=%5C%5C%20%5Ctt%5Cleadsto%20%5Cdfrac%7Bd%5BH_2%5D%7D%7Bdt%7D%3D2.25%5Ctimes%2010%5E%7B-6%7DMs%5E%7B-1%7D)
M is molarity here not metre
Answer:here is the answer
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Explanation:
Answer: It is element nitrogen. It has an atomic number of 7 and the valence electron is 5. It needs 3 electrons to complete its octet state. That's why sometimes it has the oxidation number of -3 in ammonia.
Hard question !! Is this math .. if not then oh okay cause I’m bad at math but good at everything else so let me think about it !
