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3 years ago

Which of the following of the following is the same for both hydrogen and potassium ?

1 answer:

Alex3 years ago

3 0

The answer is C. number of valence electrons. see, both pottassium and hydrogen are in group one and the group they are in shows the amount of valence electrons. hope this helped you

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34. What is the frequency of a light whose wavelength is 660 nm?

Oksanka [162]

454 teraHz I think, tell me if this is wrong

8 0

3 years ago

A 0.1064 g sample of a pesticide was decomposed by the action of sodium biphenyl. The liberated Cl- was extracted with water and

Ilya [14]

Answer:

Percentage of an aldrin in the sample is 44.41%.

Explanation:

$Cl^-+AgNO_3\rightarrow AgCl+NO_{3}^-$

Molarity of the silver nitrate solution = 0.03337 M

Volume of the silver nitrate = 23.28 mL = 0.02328 L

Moles of silver nitrate = n

$0.03337 M=\frac{n}{0.02328 L}$

n = $0.03337 M\times 0.02328 L=0.0007768 mol$

According to reaction 1 mole of silver nitrate recats with 1 moles of chloride ions.

Then 0.0007768 moles of silver nitrate will react with:

$\frac{1}{1}\times 0.0007768 mol=0.0007768 mol$ chloride ions.

In one mole of aldrin there are 6 moles of chloride ions.

Then moles of aldrin containing 0.0007768 moles chloride ions are:

$\frac{0.0007768 mol}{6}=0.0001295 mol$

Moles of aldrin present in the sample = 0.0001295 mol

Mass of 0.0001295 moles of aldrin present in the sample :

0.0001295 mol × 364.92 g/mol =0.04726 g

Percentage of an aldrin in the sample:

$\frac{0.04726 g}{0.1064 g}\times 100=44.41\%$

8 0

3 years ago

Can you use your plot to predict the absorbance of a 214 mm solution of nickel(ii) chloride and why?.

Ira Lisetskai [31]

The absorbance of the 214 mm solution of nickel(ii) chloride can be obtained by fitting it into the regression line of the calibration curve.

<h3>What is a calibration graph?</h3>

During measurements of the concentration of a solution using a spectrophotometer, it is conventional to first calibrate the instrument. The calibration is done by measuring the absorbance of various concentrations of the test solution after measuring the absorbance of the sample blank.

After the instrument has been calibrated, the absorbance of any test solution can now be obtained by fitting it into the regression line of the calibration curve.

Learn more about a spectrophotometer:brainly.com/question/18801845

6 0

2 years ago

. At 400 K, the half-life for the decomposition of a sample of a gaseous compound initially at 55.5 kPa was 340 s. When the pres

Hitman42 [59]

Answer:

The order of this half-life reaction is zero. This is a zero order reaction.

Explanation:

Step 1: Data given

At the pressure P0,1 of 55.5 kPa, the half-life is 340 s

At the pressure P0,2 of 28.9 kPa, the half-life is 178 s

Step 2: Calculate the order

(n-1) = ((log (t1/2P0,1 / t1/2P0,2)) / (log (P0,2 /P0,1)))

⇒ with t1/2P0,1 = the half-life at a pressure of 55.5 kPa = 340 s

⇒ with t1/2P0,2 = the half-life at a pressure of 28.9 kPa = 178 s

⇒ with P0,1 = the pressure of 55.5 kPa

⇒ with P0,2 = the pressure of 28.9 kPa

(n-1) = (log (340/178)) / log( 28.9/55.5)

(n-1) = log (1.91) / log(0.52)

(n-1) = 0.281 / -0.284

n-1 = -1

n = 0

The order of this half-life reaction is zero. This is a zero order reaction.

4 0

3 years ago

Idk how to do this, if you know the answer plz explain

KatRina [158]

The temperature is constant which makes it the independent variable

7 0

3 years ago

Read 2 more answers