Density is weight by volume.
First. If you divide the weight by density you can find the volume
Second you must convert the ML in to Liters.

1L=1000ml


0.38214 Liters.
The answers will be 21.5 L N2
I would say A but then again im not too sure so hope that makes it easier to somehow
The order of the answers are as follows:
B
C
D
A
We are given with a compound, Zinc (Zn) having a 1.7 x 10
^23 atoms. We are tasked to solve for it's corresponding mass in g. We need to
find first the molecular weight of Zinc, that is
Zn= 65.38 g/mol
Not that 1 mol=6.022x10^{23} atoms, hence,
1.7 x 10 ^23 atoms x 1 mol/6.022x10^{23} atoms x65.38
g/ 1mol
=18.456 g of Zn
Therefore, the mass of Zinc 18.456 g