Using accurate measurements, using pure chemicals and performing the reaction under the most ideal conditions is important to get a valuable percent yield.
<h3>How we calculate the percent yield?</h3>
Percent yield of any chemical reaction is define as the ratios of the actual yield to the theoretical yield of the product and multiply by the 100.
To get the high percent yield or actual yield of any reaction, we have to perform the reaction under ideal condition because if we not use the standard condition then we get the low rate of reaction. Reactants should be present in the pure form as impurity make unwanted products and reduce the productivity of main product and accurate amount of reactants also important for the spontaneous reaction.
Hence, options (a), (b) & (c) are correct.
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Answer:
116.3 grCO2
Explanation:
1st - we balance the equation so that it finds the same amount of elements of the product side and of the reagent side
C6H6 +15/2 O2⟶ 6CO2 +3 H2O
2nd - we calculate the limiting reagent
39.2gr C6H6*(240grO2/78grC6H6)=120 grO2
we don't have that amount of oxygen so this is the excess reagent and oxygen the limiting reagent
3rd - we use the limiting reagent to calculate the amount of CO2 in grams
105.7grO2*(264grCO2/240grO2)=116.3 grCO2
The process that describes the transfer of heat through matter by activity of the molecules would be conduction. This type of heat transfer due to the motion of electrons and ions. within a body. As molecules collide with each energy is transferred and released which cause temperature to rise or drop.<span />
Answer:
36.63 Torr
Explanation:
You need to use two expressions, one for pressure and the other with the relation of density and height of the column.
For the pressure:
P = h * d * g (1)
h is height.
d density
g gravity
The second expression put a relation between the densities and height of the column so:
d1/d2 = h1/h2 (2)
let 1 be the phthalate, and 2 the mercury.
Let's calculate first the relation of density:
d1/d2 = 13.53 / 1.046 = 12.93
Now with the first expression, we can calculate the pressure so:
P = hdg
We have two compounds so,
h1d1g = h2d2g ---> gravity cancels out
From here, we can solve for h2:
h2 = h1*(d1/d2)
replacing:
h2 = 459 / 12.53
h2 = 36.63 mm
1 mmHg is 1 torr, therefore the pressure of the gas in Torr would be 36.63 Torr
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