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svetoff [14.1K]
3 years ago
7

If y = 1/2(d + 1), find y when d = 7

Mathematics
2 answers:
almond37 [142]3 years ago
8 0

Answer:

<h3>\boxed{ \boxed{ \bold{ \purple{y = 4}}}}</h3>

Step-by-step explanation:

\sf{Given}

\sf{d = 7}

Let's find the value of y:

\sf{y =  \frac{1}{2} (d + 1)}

plug the value of d

\sf{ =  \frac{1}{2} (7 + 1)}

Add the numbers

\sf{= \frac{1}{2}  \times 8}

Calculate

\sf{ = 4}

Hope I helped!

Best regards!

nata0808 [166]3 years ago
5 0

Answer:

4

Step-by-step explanation:

Plug in 7 for d:

y= 1/2(7+1)

y=1/2(8) .... Adding what's in the parenthesis (PEMDAS)

y=4 ..... Multiply 1/2 by 8

Hope this helps:)

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Answer:

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3 years ago
A pond has 150 fish and the population decreases by 8% each day. How many days before there are 30 fish
nlexa [21]

Answer:

19 days

Step-by-step explanation:

Given

a = 150 --- initial

r = 8\% -- rate

Required

Days when the fish gets to 30

The function is exponential and as such it follows;

y = ab^x

Where x represents the number of days and y the number of fishes

Because the fishes decreases;

b = 1 - r

So, we have:

b = 1 - 8\%

Express as decimal

b = 1 - 0.08

b = 0.92

In y = ab^x

a =150

y = 30

b = 0.92

So, we have:

30 = 150 * 0.92^x

Divide both sides by 150

0.2 = 0.92^x

Take log of both sides

log(0.2) = log(0.92^x)

Apply law of logarithm

log(0.2) = x\ log(0.92)

Make x the subject

x = \frac{log(0.2)}{log(0.92)}

x = \frac{-0.6990}{-0.0362}

x = 19.309

x \approx 19

<em>Hence, it takes approximately 19 days</em>

3 0
3 years ago
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goblinko [34]

Answer:

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