Answer:
The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.
Step-by-step explanation:
Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.
But,
<P = 048°
<Q =
- 
= 0
Sum of angles in a triangle = 
<P + <Q + <S = 
048° + 0
+ <S = 
+ <S = 
<S =
- 
= 
<S = 
Applying the Sine rule,
=
= 
= 
= 
= 
⇒ y = 
= 12.703
y = 12.70 km
= 
= 
= 
⇒ x = 
= 10.0475
x = 10.05 km
Thus,
the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.
We need to find the 8 th term nth term is given as <span><span>an</span>=<span>a1</span>+(n−1)d</span>
n=8, d =-4 (common difference) <span><span>a8</span>=<span>a1</span>+(8−1)×d</span>
<span><span>a8</span>=1+7×(−4<span>)</span></span>
Write several instances of the ratio,then plot the ratios as points on the graph
M(meters) = 0.9144*y(yards)
62.831 because the firs number that is different between the two is .8 and .3, and .8 is greater regardless of the numbers that follow afterward.