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WARRIOR [948]
3 years ago
14

Is the measure of Z1 equal to the measure of Z2? Why?

Mathematics
1 answer:
VMariaS [17]3 years ago
5 0

Answer:

Angles with the same measure are congruent, so Z1 = Z2.

Step-by-step explanation:

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6) Two coastguard stations P and Q are 17km apart, with due East of P. A ship S is observed in distress on a bearing 048° fromP
adelina 88 [10]

Answer:

The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.

Step-by-step explanation:

Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.

But,

<P = 048°

<Q = 360^{o} - 324^{o}

     = 036^{o}

Sum of angles in a triangle = 180^{o}

<P + <Q + <S = 180^{o}

048° + 036^{o} + <S = 180^{o}

84^{o} + <S = 180^{o}

<S  = 180^{o} -  84^{o}

    = 96^{o}

<S = 96^{o}

Applying the Sine rule,

\frac{y}{Sin P} = \frac{x}{Sin Q} = \frac{z}{Sin S}

\frac{y}{Sin P} = \frac{z}{Sin S}

\frac{y}{Sin 48^{o} } = \frac{17}{Sin 96^{o} }

\frac{y}{0.74314} = \frac{17}{0.99452}

⇒ y = \frac{12.63338}{0.99452}

       = 12.703

y = 12.70 km

\frac{x}{Sin Q} = \frac{z}{Sin S}

\frac{x}{Sin 36^{o} } = \frac{17}{Sin 96^{o} }

\frac{x}{0.58779} = \frac{17}{0.99452}

⇒ x = \frac{9.992430}{0.99452}

      = 10.0475

x = 10.05 km

Thus,

the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.

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3 years ago
Find the sum of the first 8 terms in the sequence?
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We need to find the 8 th term nth term is given as <span><span>an</span>=<span>a1</span>+(n−1)d</span> n=8, d =-4 (common difference) <span><span>a8</span>=<span>a1</span>+(8−1)×d</span> <span><span>a8</span>=1+7×(−4<span>)</span></span>
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Write several instances of the ratio,then plot the ratios as points on the graph
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Nadusha1986 [10]
M(meters) = 0.9144*y(yards)
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3 years ago
Which is greater 62.381 or 62.831
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