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telo118 [61]
3 years ago
11

A sample of oxygen gas occupies 3.60 liters at a pressure of 1.00 atm. If the temperature is held constant, what will be the vol

ume of the oxygen gas at a pressure of 2.50 atm?
0.694 L

1.44 L

4.35 L

9.20 L
Chemistry
1 answer:
zzz [600]3 years ago
7 0
<h3><u>Answer</u>;</h3>

= 1.44 L

<h3><u>Explanation</u>;</h3>

Boyle's law states that the volume of a fixed mass of a gas is inversely proportional to its pressure at a constant temperature.

Mathematically;

<em>P α 1/V</em>

<em>PV =constant </em>

<em>Thus, P1V1 = P2V2 </em>

<em>P1 = 1.00 atm, V1 = 3.60 liters, V2 = ?, P2 = 2.50 atm</em>

<em>V2 = P1V1/P2</em>

<em>     = (1× 3.6)/2.5 </em>

<em>     = </em><u><em>1.44 L</em></u>

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Answer:

Option C. 52.057

Explanation:

The following data were obtained from the question:

Isotope >> Mass number > Percentage

A (Cr-50) > 50 >>>>>>>>>> 4.3

B (Cr-52) > 52 >>>>>>>>>> 83.8

C (Cr-53) > 53 >>>>>>>>>> 9.5

D (Cr-54) > 54 >>>>>>>>>> 2.4

Average atomic mass =?

The average atomic mass of chromium, Cr can be obtained as follow:

Average atomic mass = [(Mass of A × A%) /100] + [(Mass of B × B%) /100] + [(Mass of C × C%) /100] + [(Mass of D × D%) /100]

Atomic mass of Cr = [50×4.3)/100] + [52×83.8)/100] + [53×9.5)/100] + [54×2.4)/100]

= 2.15 + 43.576 + 5.035 + 1.296

Atomic mass of Cr = 52.057

Therefore, the atomic mass of chromium, Cr is 52.057

5 0
3 years ago
If 25.8 grams of BaO dissolve in enough water to make a 212-gram solution, what is the percent by mass of the solution?
Igoryamba
The correct answer is 12.2% BaO.

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When methyloxirane is treated with HBr, the bromide ion attacks the less substituted position. However, when phenyloxirane is tr
konstantin123 [22]

Answer:

See explanation and picture below

Explanation:

First, in the case of methyloxirane (Also known as propilene oxide) the mechanism that is taking place there is something similar to a Sn2 mechanism. Although a Sn2 mechanism is a bimolecular substitution taking place in only step, the mechanism followed here is pretty similar after the first step.

In both cases, the H atom of the HBr goes to the oxygen in the molecule. You'll have a OH⁺ in both. However, in the case of methyloxirane the next step is a Sn2 mechanism step, the bromide ion will go to the less substitued carbon, because the methyl group is exerting a steric hindrance. Not a big one but it has a little effect there, that's why the bromide will rather go to the carbon with more hydrogens. and the final product is formed.

In the case of phenyloxirane, once the OH⁺ is formed, the next step is a Sn1 mechanism. In this case, the bond C - OH⁺ is opened on the side of the phenyl to stabilize the OH. This is because that carbon is more stable than the carbon with no phenyl. (A 3° carbon is more stable than a 2° carbon). Therefore, when this bond opens, the bromide will go there in the next step, and the final product is formed. See picture below for mechanism and products.

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