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Paul [167]
3 years ago
14

15. How many grams are equal to 0.11 mole of copper(1) chromate, Cu2(CrO4)? with work please​

Chemistry
1 answer:
aleksandr82 [10.1K]3 years ago
7 0

Answer:

26.8g

Explanation:

The formula of the compound given is:

          Cu₂CrO₄

Given:

Number of moles  = 0.11

To find the mass, we use the expression below:

        Mass  = number of moles x molar mass

Molar mass of  Cu₂CrO₄ = 2(63.6) + 52 + 4(16) = 243.2g/mol

Now insert the parameters and solve;

 Mass  = 0.11 x 243.2 = 26.8g

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Acid rain is produced when _______ mixes with the water of a raindrop.
goldfiish [28.3K]

The answer should be  B - Nitrogen Dioxide.

5 0
3 years ago
2 Zn + O2 → 2 ZnO
meriva

Answer:

we need 6.0 moles of zinc (Zn)

Explanation:

Step 1: Data given

Number of moles ZnO produced = 6.0 moles

Step 2: The balanced equation

2 Zn + O2 → 2 ZnO

For 2 moles Zinc we need 1 mol Oxygen to produce 2 moles Zinc oxide

Step 3: Calculate moles zinc

For 2 moles Zn we need 1 mol O2 to produce 2 moles ZnO

For 6.0 moles 2nO produced, we need 6.0 moles of zinc (Zn) and 3.0 moles of O2 to react.

3 0
3 years ago
Pb(SO4)2 + 4 LiNO3 → Pb(NO3)4 + 2 Li2SO4
Anvisha [2.4K]

Answer:

4.5 moles of lithium sulfate are produced.

Explanation:

Given data:

Number of moles of lead sulfate = 2.25 mol

Number of moles of lithium nitrate = 9.62 mol

Number of moles of lithium sulfate = ?

Solution:

Chemical equation:

Pb(SO₄)₂ + 4LiNO₃      →     Pb(NO₃)₄ + 2Li₂SO₄

Now we will compare the moles of lithium sulfate with lead sulfate and lithium nitrate.

                       Pb(SO₄)₂        :         Li₂SO₄

                            1                :             2

                          2.25           :          2/1×2.25 = 4.5 mol

                       LiNO₃            :             Li₂SO₄

                           4                :                2

                           9.62           :             2/4×9.62 = 4.81 mol

Pb(SO₄)₂  produces less number of moles of Li₂SO₄ thus it will act as limiting reactant and limit the yield of  Li₂SO₄.      

7 0
2 years ago
A sample of 211 g of iron (III) bromide is reacted with
Alisiya [41]

FeBr₃ ⇒ limiting reactant

mol NaBr = 1.428

<h3>Further explanation</h3>

Reaction

2FeBr₃ + 3Na₂S → Fe₂S₃ + 6NaBr

Limiting reactant⇒ smaller ratio (mol divide by coefficient reaction)

  • FeBr₃

211 g of Iron (III) bromide(MW=295,56 g/mol), so mol FeBr₃ :

\tt n=\dfrac{mass}{MW}\\\\n=\dfrac{211}{295,56}\\\\n=0.714

  • Na₂S

186 g of Sodium sulfide(MW=78,0452 g/mol), so mol Na₂S :

\tt n=\dfrac{186}{78.0452}=2.38

Coefficient ratio from the equation FeBr₃ :  Na₂S = 2 : 3, so mol ratio :

\tt FeBr_3\div Na_2S=\dfrac{0.714}{2}\div \dfrac{2.38}{3}=0.357\div 0.793

So  FeBr₃ as a limiting reactant(smaller ratio)

mol NaBr based on limiting reactant (FeBr₃) :

\tt \dfrac{6}{3}\times 0.714=1.428

6 0
3 years ago
How would Bohr model show the protons in a carbon atom
MariettaO [177]

Answer:

The Bohr model show the protons in a carbon atom using the model;  "Electrons move in fixed orbits around a nucleus of protons and neutrons."

According to Bohr's model of the atoms, the Rutherford model is basically correct. This implies that Bohr model accepts the idea of a nucleus containing nucleons(protons and neutrons).

In addition, the model also postulates that electrons are found in fixed orbits. These fixed orbits are called energy levels or shells.

A graphic description of this is shown in the image attached to this answer.

Learn more: brainly.com/question/3964366

Explanation:

6 0
2 years ago
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