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patriot [66]
3 years ago
6

At a maximum level of loudness, the power output of a 75-piece orchestra radiated

Physics
1 answer:
Mashutka [201]3 years ago
4 0
7000w + 1637kw =8637kw+25.0m=loud sound
You might be interested in
Which of the following is a contact force?
3241004551 [841]

Answer:

b friction

Explanation:

Contact forces

Contact forces are forces that act between two objects that are physically touching each other. Examples of contact forces include:

Reaction force

An object at rest on a surface experiences reaction force. For example, a book on a table.

A box rests on a table. There are two arrows, equal in size but going in opposite directions, up and down, from the point where the box meets the table.

Tension

An object that is being stretched experiences a tension force. For example, a cable holding a ceiling lamp.

A box hangs from a rope. Two arrows which are equal in size act upwards and dowards from the top and bottom of the rope.

Friction

Two objects sliding past each other experience friction forces. For example, a box sliding down a slope.

A box rests on an incline. There are three arrows; one acting vertically downwards from the centre of the box’s base. One arrow acts perpendicular to the incline. One arrow acts up the incline.

Air resistance

An object moving through the air experiences air resistance. For example, a skydiver falling through the air.

A box falls from the sky. Two arrows, equal in size and opposite in direction act upwards from the box and downwards from the box

When a contact force acts between two objects, both objects experience the same size force, but in opposite directions. This is Newton's Third Law of Motion.

3 0
3 years ago
Steam enters a well-insulated nozzle at 200 lbf/in.2 , 500F, with a velocity of 200 ft/s and exits at 60 lbf/in.2 with a velocit
Ede4ka [16]

Answer:

386.2^{\circ}F

Explanation:

We are given that

P_1=200lbf/in^2

P_2=60lbf/in^2

v_1=200ft/s

v_2=1700ft/s

T_1=500^{\circ}F

Q=0

C_p=1BTU/lb^{\circ}F

We have to find the exit temperature.

By steady energy flow equation

h_1+v^2_1+Q=h_2+v^2_2

C_pT_1+\frac{P^2_1}{25037}+Q=C_pT_2+\frac{P^2_2}{25037}

1BTU/lb=25037ft^2/s^2

Substitute the values

1\times 500+\frac{(200)^2}{25037}+0=1\times T_2+\frac{(1700)^2}{25037}

500+1.598=T_2+115.4

T_2=500+1.598-115.4

T_2=386.2^{\circ}F

7 0
4 years ago
Someone please help me
professor190 [17]
The answer is A. conduction
7 0
3 years ago
what is the energy required to melt down a 12,400g Gold bar assuming its temperature goes from 23c to 1,064c
sergejj [24]

1665183.6J

Explanation:

Given parameters:

Mass of Gold = 12400g

Initial temperature = 23°C

Final temperature = 1064°C

Unknown:

Energy required to melt = ?

Solution:

The amount of heat required to cause this temperature change to heat the gold bar is given as;

   H    =   m  c Ф

 m is the mass of gold bar

  c is the specific heat capacity of gold

  Ф is the heat change

 Specific heat capacity of gold = 0.129J/g°C

  H = m c (Ф₂ - Ф₁)

 H = 12400 x 0.129 x (1064 - 23) = 1665183.6J

learn more:

Specific heat capacity brainly.com/question/7210400

#learnwithBrainly

5 0
3 years ago
A water slide is constructed so that swimmers, starting from rest at the top of the slide, leave the end of the slide traveling
Kay [80]

Answer:

4.93 m

Explanation:

According to the question, the computation of the height is shown below:

But before that first we need to find out the speed which is shown below:

As we know that

Speed = \frac{Distance}{Time}

Speed = \frac{5}{0.504}

= 9.92 m/s

Now

v^2 - u^2 = 2\times g\times h

9.92^2 = 2\times 9.98 \times h

98.4064 = 19.96 × height

So, the height is 4.93 m

We simply applied the above formulas so that the height i.e H could arrive

8 0
4 years ago
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