All categories

3 years ago

Someone please help me

Physics

1 answer:

professor190 [17]3 years ago

7 0

The answer is A. conduction

You might be interested in

A man walks along a straight path at a speed of 4 ft/s. A searchlight is located on the ground 6 ft from the path and is kept fo

BARSIC [14]

We are given that,

$\frac{dx}{dt} = 4ft/s$

We need to find $\frac{d\theta}{dt}$ when $x=8ft$

The equation that relates x and $\theta$ can be written as,

$\frac{x}{6} tan\theta$

$x = 6tan\theta$

Differentiating each side with respect to t, we get,

$\frac{dx}{dt} = \frac{dx}{d\theta} \cdot \frac{d\theta}{dt}$

$\frac{dx}{dt} = (6sec^2\theta)\cdot \frac{d\theta}{dt}$

$\frac{d\theta}{dt} = \frac{1}{6sec^2\theta} \cdot \frac{dx}{dt}$

Replacing the value of the velocity

$\frac{d\theta}{dt} = \frac{1}{6} cos^2\theta (4)^2$

$\frac{d\theta}{dt} = \frac{8}{3} cos^2\theta$

The value of $cos \theta$ could be found if we know the length of the beam. With this value the equation can be approximated to the relationship between the sides of the triangle that is being formed in order to obtain the numerical value. If this relation is known for the value of x = 6ft, the mathematical relation is obtained. I will add a numerical example (although the answer would end in the previous point) If the length of the beam was 10, then we would have to

$cos\theta = \frac{6}{10}$

$\frac{d\theta}{dt} = \frac{8}{3} (\frac{6}{10})^2$

$\frac{d\theta}{dt} = \frac{24}{25}$

Search light is rotating at a rate of 0.96rad/s

4 0

3 years ago

In a mass spectrometer, a single-charged particle (charge e) has a speed of 1.0 × 10 6 m/s and enters a uniform magnetic field o

Nonamiya [84]

Answer:

The mass is $m =6.4*10^{-28} \ kg$

Explanation:

From the question we are told that

The speed of the charge is $v = 1.0 *10^{6} \ m/s$

The magnetic field is $B = 0.20 \ T$

The radius is $r = 0.02 \ m$

The value of the charge is $e = 1.60 *10^{-19} \ C$

The centripetal acting on the charge moving in the circular orbit is mathematically represented as

$F_c = \frac{mv^2}{r }$

Now this centripetal force is due to the force exerted on the charge by the magnetic field on the charge which is mathematically represented as

$F_m = qv B sin\theta$

At the maximum of this magnetic force $\theta = 90 ^o$

$F_m = e v B sin(90)$

$F_m = e v B$

Now given that it is this magnetic force that is causing the circular motion we have that

$F_c = F_m$

=> $\frac{mv^2}{r } = ev B$

=> $m = \frac{e * B * r }{v }$

substituting values

$m = \frac{ 1.60 *10^{-19} * 0.20 * 0.020 }{1.0*10^{6} }$

$m =6.4*10^{-28} \ kg$

8 0

3 years ago

An electron that has a velocity with x component 1.6 × 106 m/s and y component 2.4 × 106 m/s moves through a uniform magnetic fi

Sergio039 [100]

Answer:

(a) 5.056 x 10^-14 N

(b) 5.056 x 10^-14 N

Explanation:

X component of velocity of electron is 1.6 × 10^6 m/s

Y component of velocity of electron is 2.4 × 10^6 m/s

X component of magnetic field is 0.025 T

Y component of magnetic field is -0.16 T

charge on electron, q = - 1.6 x 10^-19 C

Write the velocity and magnetic field in the vector forms.

$\overrightarrow{v}=1.6\times 10^{6}\widehat{i}+2.4\times 10^{6}\widehat{j}$

$\overrightarrow{B}=0.025\widehat{i}-0.16\widehat{j}$

The force on the charge particle when it is moving in the magnetic field is given by

$\overrightarrow{F}=q\left ( \overrightarrow{v}\times \overrightarrow{B} \right )$

(a) Force on electron is given by

$\overrightarrow{F}=-1.6\times 10^{-19}\left ( 1.6\times 10^{6}\widehat{i}+2.4\times 10^{6}\widehat{j} \right )\times \left ( 0.025\widehat{i}-0.16\widehat{j} \right )$

$\overrightarrow{F}=5.056\times 10^{-14}\widehat{k}$

Magnitude of force is 5.056 x 10^-14 N.

(b) Force on a proton is given by

$\overrightarrow{F}=1.6\times 10^{-19}\left ( 1.6\times 10^{6}\widehat{i}+2.4\times 10^{6}\widehat{j} \right )\times \left ( 0.025\widehat{i}-0.16\widehat{j} \right )$

$\overrightarrow{F}=-5.056\times 10^{-14}\widehat{k}$

Magnitude of force is 5.056 x 10^-14 N.

Thus, the magnitude of force remains same but the direction of force is opposite to each other.

Explanation:

4 0

3 years ago

Human population growth rates are increasing. Assuming that the biocapacity of earth does not change, what will need to happen t

iogann1982 [59]

I think it would need to decress bro

3 0

3 years ago

Read 2 more answers

Why are the lunar mountains smoothly rounded rather than having sharp, pointed peaks (as they were almost always depicted in sci

omeli [17]

Answer:

Explained

Explanation:

Lunar mountains are smoothly rounded rather than having sharp, pointed peaks because the lunar moons are formed because of the impact of asteroids and comets on its surface whereas the Earth mountains are formed because of the surface activity of volcanos, collision of land masses and activity of plate tectonics that is why they have sharp and pointed tops.

6 0

3 years ago