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3 years ago

5

The maximum allowed power dissipation for a 23.9 Ω 23.9 Ω resistor is stated to be 10.0 W . 10.0 W. Calculate the largest curren

t that this resistor can take safely without burning out.

1 answer:

damaskus [11]3 years ago

3 0

Answer:

0.65 A.

Explanation:

Given:

Pmax = 10 W

R = 23.9 Ω

Formula for calculating power,

P = I × V

= I^2 × R

I^2 = 10/23.9

I = 0.65 A.

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Answer:

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Explanation:

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q is the distance of the image from the mirror

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And the positive sign means that the image is real.

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3 years ago

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34kurt

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