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olga55 [171]
3 years ago
5

The maximum allowed power dissipation for a 23.9 Ω 23.9 Ω resistor is stated to be 10.0 W . 10.0 W. Calculate the largest curren

t that this resistor can take safely without burning out.
Physics
1 answer:
damaskus [11]3 years ago
3 0

Answer:

0.65 A.

Explanation:

Given:

Pmax = 10 W

R = 23.9 Ω

Formula for calculating power,

P = I × V

= I^2 × R

I^2 = 10/23.9

I = 0.65 A.

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Answer:

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Explanation:

In order to find electric field, we can use the formula of power density

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E = electric field strength in V/m

Z = impedance of free space = 120 * π

E = sqrt(Pd * Z) -----> re-arranging it for E

before solving, convert Pd unit into W/m^2  

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Solving for E:

E= sqrt(50 * 120 * π)

E = 137.3 V/m  

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In order to find the peak amplitude of the oscillating field will therefore be 137.3 * sqrt(2) = 194 V/m

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Explanation:

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