1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ne4ueva [31]
3 years ago
7

What angular speed (in revolutions per minute) is needed for a centrifuge to produce an acceleration of 944 times the gravitatio

nal acceleration 9.8 m/s 2 at a radius of 7.02 cm ? Answer in units of rev/min.
Physics
1 answer:
sdas [7]3 years ago
5 0

Answer:

3335.3r/m

Explanations:

For an object in the centrifuge it is assumed to be traveling at a constant circular speed. In this case there is no tangential acceleration on the object. It is only accelerated outwards at an acceleration given by v^2/r where v is the constant speed and r is the radius of the circle in which it is moving.

The required acceleration of the object in the centrifuge is 944 times that of the gravitational acceleration. This is equal to 944*9.8 = 9251.2 m/s^2.

The radius of the centrifuge is 7.02 cm = 7.02*10^-2 m.

To produce the required acceleration the linear velocity is v, where

a =v^2/(7.02*10^-2) = 9251.2m/s

=> v^2 = 9251.2*7.02*10^-2

v^2 = 649.43

v = √(649.43)

=> v = 25.484 m/s

The angular velocity in terms of revolutions per second is 25.484/(2*pi*7.02*10^-2) = 56.7 revolutions/second.

For revolutions/minutes

Since 60s - 1m

1s - 0.017m

So 56.7r/0.017m = 3335.3r/m

The centrifuge has to rotate at 3335.3 revolutions/minutes to achieve an acceleration equal to 944 times that of the gravitational acceleration.

You might be interested in
An object is 45.0 kg here on Earth. What is its mass on Jupiter if the acceleration
puteri [66]

Answer:

B. 45.0 kg

Explanation:

On earth the object has ;

Mass = 45 kg

acceleration = 9.81 m/s²

On Jupiter, acceleration is  24.79 m/s²

The mass of this object on Jupiter will be 45 kg. It will not change. Mass of an object will only change when you remove part of the object from it or add to it another part. The mass is the same on Earth and on Jupiter. However, due to increased acceleration on Jupiter , the weight will change/ increase because;

Weight = mass * acceleration

<u>On Earth </u>

Weight of the object will be : 45 *  9.81 = 441.45 kg

<u>On Jupiter</u>

Weight of the object will be : 45*24.79 =1115.55 kg

8 0
3 years ago
Energy is transmitted only in indivisible discrete quantities. True or False
alex41 [277]

Answer:

False

Explanation:

From the fact that light is emitted in portion, it does not follow that light ray is discrete in structure.

The way Einstein put it was that if a beer is always sold in pint bottles, that does not mean that beer contain of indivisible pint bottles. Yet experiments in which light  knocked electrons out of materials insistently made the point that light is absorbed only in the form of discrete portions. An emitted portion or quantum of light energy retains it's individuality in subsequent events as well.

This concept was first stated by Einstein in 1905. From the heuristic point of view that he developed light is always made up of discrete portions possessing energy and momentum.

5 0
3 years ago
There is a potential difference of 1.1 V between the ends of a 10 cm long graphite rod that has a cross-sectional area of 0.90 m
Serga [27]

Explanation:

It is given that,

Potential difference between the ends of a rod, V = 1.1 V

Length of the rod, l = 10 cm = 0.1 m

Area of cross section of the rod, A=0.9\ mm^2=9\times 10^{-7}\ m^2

The resistivity of graphite, \rho=7.5\times 10^{-6}\ \Omega-m

(a) Let R is the resistance of the rod. It is given by :

R=\rho \dfrac{l}{A}

R=7.5\times 10^{-6}\times \dfrac{0.1}{9\times 10^{-7}}

R=0.833\ \Omega

So, the resistance of the rod is 0.833 ohms.

(b) Let I is the current flowing in the wire. It can be calculated using the Ohm's law as :

I=\dfrac{V}{R}

I=\dfrac{1.1\ V}{0.833\ \Omega}

I = 1.32 A

(c) Let E is the electric field inside the rod. The electric field in terms of potential difference is given by :

E=\dfrac{V}{l}

E=\dfrac{1.1\ V}{0.1\ m}

E = 11 V/m

Hence, this is the required solution.

8 0
3 years ago
What three factors affect the acceleration of an object?
nignag [31]

Explanation:

The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased

7 0
3 years ago
Plants make ___________ using carbon dioxide, water and energy from the sun.
gizmo_the_mogwai [7]

Answer:

I think it's carbohydrates

Explanation:

The energy from light causes a chemical reaction that breaks down the molecules of carbon dioxide and water and reorganizes them to make the sugar (glucose) and oxygen gas.

7 0
3 years ago
Other questions:
  • Rust forms because iron and oxygen are highly elements
    7·1 answer
  • Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar. In a survey conduc
    14·1 answer
  • A proton with a velocity in the positive x-direction enters a region where there is a uniform magnetic field B in the positive y
    13·1 answer
  • 21 kg brick v=6.1 m/s sticks to a 2.9 kg cart v=.26 m/s
    8·1 answer
  • A racing car increases its speed from 10 m/s to 50 m/s over a distance of 60 m.
    11·1 answer
  • Why should you try to avoid food containing corn sugar dextrose or sucrose
    14·2 answers
  • 4.The equation for Kinetic Energy is 1/2 x m x v2. Calculate the KE when the mass is 5 kg and the velocity is 4 m/s.
    8·1 answer
  • 14. Saeed is pulling a 6 kg heavy rock with an upward force of 40 N but does not succeed to lift it up. What is the magnitude of
    7·1 answer
  • Marisol breaks her leg when falling out of a tree.Why did her leg break?
    15·2 answers
  • 2 H2O2-&gt; 2H20+02
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!