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3 years ago

21 kg brick v=6.1 m/s sticks to a 2.9 kg cart v=.26 m/s

Physics

1 answer:

vovikov84 [41]3 years ago

5 0

Answer:

v = 6.05 m/s

Explanation:

The mass of the brick, M = 21 kg

The velocity of the brick, U = 6.1 m/s

The mass of the cart, m = 2.9 kg

The velocity of the cart, u = 0.26 m/s

The combined mass of the brick and the cart, v = ?

According to the law of conservation of linear momentum,

Combined final momentum = sum of the initial momentum

(M + m)v = MU + mu

v = MU + mu / M + m

= 21 x 6.1 + 2.1 x 0.26 / (21 + 0.26)

= 6.05 m/s

Hence, the combined velocity of the cart and the brick is, v = 6.05 m/s

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