Answer:
v = 6.05 m/s
Explanation:
The mass of the brick, M = 21 kg
The velocity of the brick, U = 6.1 m/s
The mass of the cart, m = 2.9 kg
The velocity of the cart, u = 0.26 m/s
The combined mass of the brick and the cart, v = ?
According to the law of conservation of linear momentum,
Combined final momentum = sum of the initial momentum
(M + m)v = MU + mu
v = MU + mu / M + m
= 21 x 6.1 + 2.1 x 0.26 / (21 + 0.26)
= 6.05 m/s
Hence, the combined velocity of the cart and the brick is, v = 6.05 m/s
