Answer:
16 m/s , hope this helps.
Answer:
The answer is 80 kN . m (clockwise)
Explanation:
As,
M = P x L
Here, the towline exerts a force is P.
Substituting P for 4000N.
M = -4000N x 20m
= -80000N.m
= 80kN.m
Maximum moment about the point O is 80kN.m (Clockwise)
Answer:
0.82052 m
Explanation:
potential energy of spring = kinetic energy
=> 0.5kx^2 = 0.5mv^2
=> 

v= 3.11127 m/s
angle = 37°
thus height = distance×sin(37) = D×0.60182
Also,
m×g×h = 0.5×m×v^2
=> 2×9.8×D×0.60182 = 0.5×2×3.11127×3.11127
=> D = 0.82052 m
The magnitude of the change in momentum of the block between zero and 4. 0 seconds is
dp=1.6m/s
<h3>What is the magnitude of the change in momentum of the block between zero and 4. 0 seconds?</h3>
Generally, the equation for the kinematics equation is mathematically given as
x=x+ut+0.5at^2
Therefore
1.6=0+0+0.5*a*1^2
a=0.2m/s^2
In conclusion, change in momentum
dP=mv-mu
2.0*0.8-0
dp=1.6m/s
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