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Alex787 [66]
3 years ago
9

What are the domain and range of the relation {(–9, 5), (1, 5), (6, 11), (7, –10)}?

Mathematics
1 answer:
Fynjy0 [20]3 years ago
4 0
So these are ordered pairs
(x,y)
x=input
y=output

x=domain
y=range

so the domain is all the first numbers
range is all the second numbers

so (-9,5), (1,5), (6,11), (7,-10)
doman={-9,1,6,7}
range={5,11,-10} (since the 5 repeats we don't need to rite it again

answer is B
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Air pressure may be represented as a function of height (in meters) above the
denis-greek [22]

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Step-by-step explanation:

<h3> The complete exercise is: "Air pressure may be represented as a function of height (in meters) above the surface of the Earth, as shown below:</h3><h3>  P(h) =P_0e^{-0.00012h} </h3><h3> In this function P_o   is the air pressure at the surface of the earth, and h is the height above the surface of the Earth, measured in meters. At what height will the air pressure equal 50% of the air pressure at the surface of the Earth"</h3><h3></h3>

Given the following function:

P(h) =P_0e^{-0.00012h}

In order to calculate at what  height the air pressure will be equal 50% of the air pressure at the surface of the Earth, you can follow these steps:

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0.5P_o=P_0e^{-0.00012h}

2. Finally, you must solve for h.

Remember the following property of logarithms:

ln(b)^a=a*ln(b)\\\\ln(e)=1

Then, you get this result:

0.5P_o=\frac{P_o}{e^{0.00012h}}\\\\(0.5P_o)(e^{0.00012h})=P_o\\\\e^{0.00012h}=\frac{P_o}{0.5P_o}\\\\ln(e)^{0.00012h}=ln(2)\\\\0.00012h*1=ln(2)\\\\h=\frac{ln(2)}{0.00012}\\\\h=5576.2

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4 years ago
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