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Genrish500 [490]
3 years ago
11

For each pair below, select the sample that contains the largest number of moles.

Chemistry
2 answers:
Deffense [45]3 years ago
8 0

Answer:

A: 2.50 g n2

B:21.5 g N2

C:0.081 CO2

Explanation:

dybincka [34]3 years ago
7 0

Answer:

Explanation:

Pair A:

Answer:

nitrogen

Moles of oxygen:

Number of moles = mass/ molar mass

Number of moles = 2.50 g/ 32 g/mol

Number of moles = 0.08 mol

Moles of nitrogen:

Number of moles = mass/ molar mass

Number of moles = 2.50 g/ 28 g/mol

Number of moles = 0.09 mol

Pair B:

Answer:

nitrogen

Moles of nitrogen:

Number of moles = mass/ molar mass

Number of moles = 21.50 g/ 28 g/mol

Number of moles = 0.77 mol

Moles of carbon dioxide:

Number of moles = mass/ molar mass

Number of moles = 15.2 g/ 44 g/mol

Number of moles = 0.341 mol

Pair C:

Answer:

Both have same number of moles.

Moles of oxygen:

Number of moles = mass/ molar mass

Number of moles = 0.054 g/ 32 g/mol

Number of moles = 0.002 mol

Moles of carbon dioxide:

Number of moles = mass/ molar mass

Number of moles = 0.081 g/ 44 g/mol

Number of moles = 0.002 mol

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What volume (mL) of the partially neutralized stomach acid was neutralized by NaOH during the titration? (portion of 25.00 mL sa
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The question is incomplete, here is the complete question:

What volume (mL) of the partially neutralized stomach acid having concentration 2 M was neutralized by 0.1 M NaOH during the titration? (portion of 25.00 mL NaOH sample was used; this was the HCl remaining after the antacid tablet did it's job)

<u>Answer:</u> The volume of HCl neutralized is 1.25 mL

<u>Explanation:</u>

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

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n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=2M\\V_1=?mL\\n_2=1\\M_2=0.1M\\V_2=25mL

Putting values in above equation, we get:

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