Answer:
72.4%
Explanation:
Step 1: Write the balanced equation
2 Cu + S ⇒ Cu₂S
Step 2: Calculate the theoretical yield, in moles, from 0.0970 moles of Cu
The molar ratio of Cu to Cu₂S is 2:1.
0.0970 mol Cu × 1 mol Cu₂S/2 mol Cu = 0.0485 mol Cu₂S
Step 3, Convert the theoretical yield to mass
The molar mass of Cu₂S is 159.16 g/mol.
0.0485 mol × 159.16 g/mol = 7.72 g
Step 4: Calculate the percent yield
We will use the following expression.
%yield = experimental yield/theoretical yield × 100%
%yield = 5.59 g/7.72 g × 100% = 72.4%
Answer:
A
Explanation:
Halogens have 7 electrons in their valence shell and requires just one electron to achieve their stable structure. Because of this they have high electron affinity and hence high electronegativity and they are strong oxidizing agents. Oxidation is the loss of electrons . Halogens have a high readiness to take electrons which a metal loses thereby oxidizing it. The other options are wrong as they involve compounds and not the elemental form as stated in the question.
It’s either a or b for sure
You would need 20 moles of H2 to get 10 moles of CH4 because the ration of H2 to CH4 is 2:1