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2 years ago

1. How does cellular respiration add carbon to the atmosphere?

1 answer:

8 0

Glucose and oxygen are changed into energy and carbon dioxide during cellular respiration and that’s how carbon dioxide is released in the air.

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What is organic chemistry

tester [92]

Answer:

Organic chemistry

Explanation:

Organic chemistry is part of the chemistry that studies carbon compounds, which also use organic compounds, which have characteristics.

5 0

2 years ago

How many moles in 1.00g of salicylic acid?

salantis [7]

Answer:- 0.00724 moles.

Solution:- Grams of salicylic acid are given and it asks to calculate the moles.

For the moles, we divide the grams by the molar mass.

Formula of salicylic acid is $C_7H_6O_3$

Molar mass = 7(12.01)+6(1.01)+3(16.00)

= 84.07+6.06+48.00

= 138.13 gram per mol

We could make the dimensional analysis set up for showing unit cancellation and have the moles.

$1.00g(\frac{1mol}{138.13g})$

= 0.00724 moles

So, there will be 0.00724 moles of salicylic acid in it's 1.00 gram.

7 0

3 years ago

Write the following numbers in standard notation, maintaining the same number of significant figures.

Alexxandr [17]

Answer:

6.104x10^2=610.4

9.5x10^3=9500

Explanation:

7 0

3 years ago

In thermodynamics, we determine the spontaneity of a reaction by the sign of ΔG. In electrochemistry, spontaneity is determined

faltersainse [42]

Answer:

For A: The standard cell potential of the reaction is 4.4 V

For B: The standard Gibbs free energy of the reaction is $-8.50\times 10^5J$

For C: The reaction is spontaneous as written.

Explanation:

For A:

The given chemical reaction follows:

$2Li(s)+Cl_2(g)\rightarrow 2Li^+(aq.)+2Cl^-(aq.)$

The given half reaction follows:

Oxidation half reaction: $Li(s)\rightarrow Li^+(aq.)+e^-;E^o_{Li^+/Li}=-3.04V$ ( × 2)

Reduction half reaction: $Cl_2(g)+2e^-\rightarrow 2Cl^-(aq.);E^o_{Cl_2/2Cl^-}=+1.36V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction.

Here, chlorine will undergo reduction reaction will get reduced.

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

$E^o_{cell}=1.36-(-3.04)=4.4V$

Hence, the standard cell potential of the reaction is 4.4 V

For B:

Relationship between standard Gibbs free energy and standard electrode potential follows:

$\Delta G^o=-nFE^o_{cell}$

where,

n = number of electrons transferred = $2mol\text{ e}^-$

F = Faradays constant = $96500J/V.mol\text{ e}^-$

$E^o_{cell}$ = standard cell potential = 4.4 V

Putting values in above equation, we get:

$\Delta G^o=-2\times 96500\times 4.4=-849200J=-8.50\times 10^5J$

Hence, the standard Gibbs free energy of the reaction is $-8.50\times 10^5J$

For C:

For a reaction to be spontaneous, the standard Gibbs free energy change of the reaction must be negative.

From above, the standard Gibbs free energy change of the reaction is coming out to be negative.

Hence, the reaction is spontaneous as written.

7 0

3 years ago

What will occur if the velocity of the gas molecules colliding with the sides of the container increases?

yanalaym [24]

The pressure of the gas will increases

6 0

3 years ago

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