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ratelena [41]
2 years ago
11

1.

Chemistry
1 answer:
Makovka662 [10]2 years ago
7 0

Answer:

1) 70

2) conduction

3) The ground absorbs the solar radiation and

releases it throughout the later afternoon.

4) transpiration

5) convection

6) cumulonimbus

7) reflectivity of Earth’s surface

8) As temperature increases, air pressure

increases.

9) thermosphere

10) convection cells, pressure belts, and the

Coriolis effect

11) radiation

12) pollen

13) scattering

14) thermosphere

15) The different types of clouds are:

<u>cumulus:</u><em><u> </u></em><em>Cumulus clouds are clouds which have flat bases and are often described as "puffy", "cotton-like" or "fluffy" in appearance. Their name derives from the Latin cumulo-, meaning heap or pile. </em>

<u>cirrus</u><em>:</em><em> </em><em>Cirrus is a genus of atmospheric cloud generally characterized by thin, wispy strands, that typically appear white or light grey. The name is derived from the Latin word cirrus, meaning 'ringlet' or 'curling lock of hair'. Such a cloud can form at any altitude between 5,000 and 13,700 m above sea level.</em>

<u>stratus:</u><em> </em><em>Stratus clouds are low-level clouds characterized by horizontal layering with a uniform base, as opposed to convective or cumuliform clouds that are formed by rising thermals.</em>

<u>nimbus</u>: <em>Nimbostratus clouds are dark, grey, featureless layers of cloud, thick enough to block out the Sun and produce persistent rain. Height of base: 2,000 - 10,000 ft. Shape: Bands or areas of individual cells. Latin: nimbus - rainy cloud; stratus - flattened or spread out. Precipitation: Continuous rain or snow likely.</em>

16) the tradewinds

17) the location’s latitude

18) Cirrus clouds

19) the ozone layer

20) Global winds are created by both the spin of

the Earth (Coriolis effect) and the differences

in temperature between the equator and

the polar areas. These winds are often

grouped together as trade winds, easterlies,

and westerlies.

21) nitrogen

22) the Miller-Urey hypothesis

the Oparin-Haldane hypothesis

23) ammonia gas

24) cumulus

25) It determines the mass of water in a volume of air

Explanation:

please please please mark me as brainliest

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In a ketone, the carbonyl group is bonded to how many hydrogen atoms? none one two three four
allochka39001 [22]

Answer:

None of carbonyl group is attached to hydrogen atoms.

Explanation:

Ketone is a group in which one carbonyl group is attached to two R ( the alkyl group) .

And the group in which two hydrogen is attached to R is called as aldehyde (formaldehyde).

And when one hydrogen and one alkyl group is attached to R. It is called as acetaldehyde from aldehyde family.

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A jet is goes from 180km/s to 139km/s in 22 seconds. What is it's acceleration?
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180 km/s V= 25



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50.00 mL of 0.10 M HNO 2 (nitrous acid, K a = 4.5 × 10 −4) is titrated with a 0.10 M KOH solution. After 25.00 mL of the KOH sol
boyakko [2]

Answer:

b. 3.35

Explanation:

To calculate the pH of a solution containing both acid and its salt (produced as a result of titration) we need to use Henderson’s equation i.e.

pH = pKa + log ([salt]/[acid])     (Eq. 01)

Where  

pKa = -log(Ka)        (Eq. 02)

[salt] = Molar concentration of salt produced as a result of titration

[acid] = Molar concentration of acid left in the solution after titration

Let’s now calculate the molar concentration of HNO2 and KOH considering following chemical reaction:

HNO2 + KOH ⇆ H2O + KNO2    (Eq. 03)

This shows that 01 mole of HNO2 and 01 mole of KOH are required to produce 01 mole of KNO2 (salt). And if any one of them (HNO2 and KOH) is present in lower amount then that will be considered the limiting reactant and amount of salt produced will be in accordance to that reactant.

Moles of HNO2 in 50 mL of 0.01 M HNO2 solution = 50/1000x0.01 = 0.005 Moles

Moles of KOH in 25 mL of 0.01 M KOH solution = 25/1000x0.01 = 0.0025 Moles

As it can be seen that we have 0.0025 Moles of KOH therefore considering Eq. 03 we can see that 0.0025 Moles of KOH will react with only 0.0025 Moles of HNO2 and will produce 0.0025 Moles of KNO2.

Therefore

Amount of salt produced i.e [salt] = 0.0025 moles       (Eq. 04)

Amount of acid left in the solution [acid] = 0.005 - 0.0025 = 0.0025 moles (Eq.05)

Putting the values in (Eq. 01) from (Eq.02), (Eq. 04) and (Eq. 05) we will get the following expression:

pH= -log(4.5x10 -4) + log (0.0025/0.0025)

Solving above we get  

pH = 3.35

5 0
3 years ago
hat is the pressure of CO(g) in equilibrium with the CO2(g) and O2(g) in the atmosphere at 25 ????C? The partial pressure of O2(
Lubov Fominskaja [6]

Answer:

The partial pressure of CO is 5.54x10⁻⁴⁹atm. You shouldn't worry because it is very low pressure

Explanation:

First, the balanced reaction is:

CO + 1/2O₂ → CO₂

The energies of formation are:

ΔG(CO)=-137.168kJ/mol

ΔG(O₂)=0

ΔG(CO₂)=-394.359kJ/mol

The energy of the reaction is:

delta-G_{reaction} =delta-G_{CO_{2} } -(delta-G_{CO} +1/2delta-G_{O_{2} } )\\delta-G_{reaction}=-394.359-(-137.168+0)=-257.191kJ/mol

The expression for calculate the partial pressure of CO is:

p_{CO} =\frac{p_{CO2} }{p_{O_{2} }^{1/2}*exp^{-\frac{delta-G}{RT} }   } \\p_{CO}=\frac{3x10^{-4} }{0.2^{1/2}*exp(-\frac{-257.191*1000}{8.314*298} ) } \\p_{CO}=5.54x10^{-49} atm

5 0
3 years ago
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