X=y+2
x=3y
2x=4y+2
4y+2=2(y+2)
4y+2=2y+4
2y+2=4
2y=2
y=1
x=3
1+3=4
Their sum is 4
Hope this helps :)
Answer:
2 (x + 3)^2 - 2
Step-by-step explanation:
1. Factor the 2 out of the equation (don't forget about it - it will be used later). This gives you x^2 + 6x + 7
2. Subtract the 7 over. This gives you x^2 + 6x = -7
3. Take b (6), divide it by 2 (3), and square it (9). Then add that to both sides of the equation. This gives you x^2 + 6x + 9 = 2
4. Factor the left side of the equation. This gives you (x + 3)^2 = 2
5. Subtract the 2 over. This gives you (x + 3)^2 - 2
6. Remember that 2 we factored out of the equation earlier? Well that goes in front of the parentheses now, giving you the final answer of 2 (x + 3)^2 -2
x = 2
Collect terms in x to one side of the equation and numeric values on the other side.
1 + 4x = - 5 + 7x ( subtract 7x from both sides )
1 + 4x - 7x = - 5
1 - 3x = - 5 ( subtract 1 from both sides )
- 3x = - 6 ( divide both sides by - 3 )
x = = 2