Missing in your question the K constant value =2.99X10^-7
The reaction equation:
SOCl2 ⇄ SO2 +Cl2
initial 0.195 0 0
-X +X +X
final (0.195-X) X X
K= [SO2][Cl2]/SOCl2
by substitution
2.99X10^-7 = (X)(X)/(0.195-X)
2.99X10^-7 = X^2 / (0.195-X) by solving this equation
∴X = 0.00024 = 2.4 X10^-4
∴[Cl2] = 2.4X10^-4 m
Answer:
3.65 g / ml correct to 3 sig. fig.
Explanation:
The computation of the concentration required is shown below:
As we know that
[A] = mass of solute ÷ volume of solution
Before that first find the mass of solute
Given that
Initial weight = 5.55g
And,
Final weight = 92.7 g
So,
Mass of KCl is
= 92.7 - 5.55
= 87.15 g ~ 87.2 g
Now the KCi is fully dissolved, so the volume is 23.9 ml
So, concentration is
= 87.2 g ÷ 23.9 ml
= 3.65 g / ml correct to 3 sig. fig.
The name is Copper(II) Oxide and/or Cupric Oxide.
Cu is Copper and O is Oxygen.
Usually when the Oxygen ion is placed after another, it's name is Oxide.
Answer:
There are 5 significant digits in 0.23100.
Explanation:
This is because all non-zero digits are considered significant and zeros after decimal points are considered significant.
