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marin [14]
3 years ago
9

Which object has the lowest density beach ballwatersand​

Chemistry
1 answer:
Ivahew [28]3 years ago
4 0
Beach ball 〽️〽️〽️〽️〽️〽️〽️〽️〽️〽️〽️〽️
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LIMITING REACTANT!! Please help I’m very confused.
alexira [117]

Answer:

We'll have 1 mol Al2O3 and 3 moles H2

Explanation:

Step 1: data given

Numer of moles of aluminium = 2 moles

Number of moles of H2O = 6 moles

Step 2: The balanced equation

2Al + 3H2O → Al2O3 + 3H2

Step 3: Calculate the limiting reactant

For 2 moles Al we need 3 moles H2O to produce 1 mol Al2O3 and 3 moles H2

Aluminium is the limiting reactant. It will completely be consumed (2 moles).

H2O is in excess. There will react 3/2 * 2 = 3 moles

There will remain 6 - 3 = 3 moles

Step 4: Calculate moles products

For 2 moles Al we need 3 moles H2O to produce 1 mol Al2O3 and 3 moles H2

For 2 moles Al we'll have 2/1 = 1 mol Al2O3

For 2 moles Al We'll have 3/2 * 2 = 3 moles H2

We'll have 1 mol Al2O3 and 3 moles H2

8 0
3 years ago
7 Los organismos que se alimentan de material orgánico incluye:<br>​
kipiarov [429]

Answer:

que

Explanation:

8 0
3 years ago
Chemical digestion would not be possible without _____, which speed up the rate of chemical reactions in your body?
Mashutka [201]
Enzymes in our body increases the speed of chemical digestion.
7 0
3 years ago
Read 2 more answers
Four animals were fleeing from a wildfire. All of them were running at a speed of 30 miles per hour. Which one has the greatest
RUDIKE [14]

Answer: I don’t know lol

Explanation:  I am so sorry I thought this was easy

6 0
3 years ago
Read 2 more answers
A chemical reaction takes place inside a flask submerged in a water bath. The water bath contains 8.10kg of water at 33.9 degree
lions [1.4K]

Answer:

The new temperature of the water bath 32.0°C.

Explanation:

Mass of water in water bath ,m= 8.10 kg = 8100 g ( 1kg = 1000g)

Initial temperature of the water = T_1=33.9^oC=33.9+273K=306.9 K

Final temperature of the water = T_2

Specific heat capacity of water under these conditions =  c = 4.18 J/gK

Amount of energy lost by water = -Q = -69.0 kJ = -69.0 × 1000 J

( 1kJ=1000 J)

Q=m\times c\times \Delta T=m\times c\times (T_2-T_1)

-69.0\times 1000 J=8100 g\times 4.18 J/g K\times (T_2-306.9 K)

-69,000.0 J=8100 g\times 4.18 J/g K\times (T_2-306.9 K)

T_2=304.86 K=304.86 -273^oC=31.86^oC\approx 32.0^oC

The new temperature of the water bath 32.0°C.

5 0
3 years ago
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