Answer:3.92475J
Explanation:
ideal gas equation
PV=nrT
P=pressure
V=volume 9*5*14=630m^3
n=mole
Mole=mass/molecular mass
molecular mass of air=28.1g/mol
R=gas constant
T=temperature in kelvin
1.01*10^5*630=(m/28)*8.314j/molK *273K
784959.5677356082g
784.95kg
Kinetic energy=0.5*m*v^2
Velocity of air
0.5*784.95kg*0.1^2
K.E=3.92475J
6
The answer you are looking for is:
A. Force
Hope that helps!!
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Lets use the expression
F = k*x
Where k is the spring constant [N/m]
And x the distance from the equilibrium position.
This force is equal to the force due to the acceleration of gravity
F = k*x = m*g
F = 525[N/m]* 0.30 [m] = 157.5 [N]
157.5 [N] = m *10[m/s**2] ...................> m = 15.75 kg
Answer:
a) rM<3.456* 10e8 m
b) a= 3.33 · 10e-3 m/s²
Explanation:
mA -mass of the astronaut
mE=5.98*10 24 kg mass of the Earth
mM= 7.36* 10 22kg mass of the Moon
r -distance between Eart and Moon, r= 3.84*10 8 m
rM - the point where the forces from the Earth and the Moon are the same
g gravitanioal const5ant g=6.67*10 -11 Nm2/kg2
FE=FM
g*mE*mA/(r-rM)2=g*mM*mA/(rM2) yields
mE/(r-rM)2=mM/rM2
sqrt (mE/mM)*(r-rM)=rM
rM*(1+sqrt (mE/mM))=sqrt (mE/mM)*r
rM=(sqrt (mE/mM)*r)/(1+sqrt (mE/mM))
rM=9*3.84*10 8m/10
<u>rM=3.456* 10 8 m</u>
less than that distance is the asked one
b) F=Fg
mA*a=g*mA*mE/(rM2)
a=g*mE/(rM2)
a=6.67*10 -11 Nm2/kg2 *5.97*10 24kg/ (3.456 10 8m)2
a=3.33* 10 -3 m/s2
The center of mass is given with this formula:
Velocity is:
So, for the velocity of the center of mass we have:
In our case it is: