Answer:
Final velocity, v = 0.28 m/s
Explanation:
Given that,
Mass of the model,
Speed of the model,
Mass of another model,
Initial speed of another model,
To find,
Final velocity
Solution,
Let V is the final velocity. As both being soft clay, they naturally stick together. It is a case of inelastic collision. Using the conservation of linear momentum to find it as :
V = 0.28 m/s
So, their final velocity is 0.28 m/s. Hence, this is the required solution.
Answer:
<em>mass of the ice is 254980463.8T kg</em>
<em>where T is the value of the thickness omitted in the question.</em>
Explanation:
The ice on Walden Pond is .......... thick. The area of the pond is approximately equal to the area of a circle with radius 297 m. Find the mass of the ice. Answer in kg.
<em>The value of the thickness of the ice T is omitted, but I will show the solution, and the real answer can be gotten by multiplying the final calculated answer here by the thickness of the ice omitted.</em>
Given the radius of the equivalent circle of the ice = 297 m'
the area of the ice can be gotten from area A = =
= 277152.678 m^2
recall that the density of ice p ≅ 920 kg/m^3
also,
density of ice p = (mass of ice, m) ÷ (volume of ice, v)
i.e p = m/v
and,
m = pv
substituting the value of the density of water p into the equation, we have,
mass of the ice, m = 920v ....... equ 1
The volume of the ice above will be = (area of the ice, A) x (thickness of the ice, T)
i.e v = AT
substituting the value of area A into the equation, we have
v = 277152.678T ......equ 2
substitute value of v into equ 1
mass of the ice, m = 920 x (277152.678T)
mass of the ice, m = 254980463.8T kg
where T is the thickness of the ice
NB: To get the mass, multiply this answer with the thickness T given in the question.
Answer:
Explanation:
Capacity of a parallel plate capacitor C = ε₀ A/ d
ε₀ is permittivity whose value is 8.85 x 10⁻¹² , A is plate area and d is distance between plate.
C =( 8.85 X10⁻¹² X 27 X 10⁻⁴ ) / 3 X 10⁻³
= 79.65 X 10⁻¹³ F.
potential diff between plate = Charge / capacity
= 4.8 X 10⁻⁹ / 79.65 X 10⁻¹³
= 601 V
Electric field = V/d
= 601 / 3 x 10⁻³
= 2 x 10⁵ N/C
Force on proton
= charge x electric field
1.6 x 10⁻¹⁹ x 2 x 10⁵
= 3.2 x 10⁻¹⁴
Acceleration a = force / mass
= 3.2 x 10⁻¹⁴ / 1.67 x 10⁻²⁷
= 1.9 x 10¹³ m s⁻²
Distance travelled by proton = 3 x 10⁻³
3 x 10⁻³ = 1/2 a t²
t =
t = 1.77 x 10⁻⁸ s