Answer:0.302
Explanation:
Given
mass of crate m=27 kg
Force required to set crate in motion is 80 N
Once the crate is set in motion 56 N is require to move it with constant velocity
i.e. 80 N is the amount of force needed to just overcome static friction and 56 is the kinetic friction force
thus
![f_s(static\ friction)=\mu \cdot N](https://tex.z-dn.net/?f=f_s%28static%5C%20friction%29%3D%5Cmu%20%5Ccdot%20N)
where
is the coefficient of static friction and N is Normal reaction
![N=mg](https://tex.z-dn.net/?f=N%3Dmg)
![f_s=\mu mg](https://tex.z-dn.net/?f=f_s%3D%5Cmu%20mg)
![\mu mg=80](https://tex.z-dn.net/?f=%5Cmu%20mg%3D80)
![\mu =\frac{80}{27\times 9.8}](https://tex.z-dn.net/?f=%5Cmu%20%3D%5Cfrac%7B80%7D%7B27%5Ctimes%209.8%7D)
![\mu =0.302](https://tex.z-dn.net/?f=%5Cmu%20%3D0.302%20)
The black squirrel has zero kinetic energy (if it's not moving) and lower gravitational potential energy than the red squirrel or zero gravitational potential energy if the ground is assumed to be zero gravitational potential line.
The answers to your question are,
Independent, Dependent, and Control.
-Mabel <3
<span>True
</span><span>True
</span><span>False*
</span><span>False*
</span><span>True
</span><span>True
</span><span>False
A,B,AB,O
10.)?
11.)</span><span>water
carbon dioxide
12.)</span><span>geocentric
</span>13.)<span>Juptier</span>