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lidiya [134]
3 years ago
5

While skateboarding at 19 km/h, Alana throws a tennis ball at 11 km/h to her friend Oliver. If Alana is the reference frame, the

speed of the tennis ball is
Physics
2 answers:
ANTONII [103]3 years ago
5 0

Well, you see, I don't think Alana really is the reference frame. 
Call me paranoid, but I think you changed the reference frame
during the question, and didn't tell us.

In which reference frame is the 19 km/hr measured ?
It CAN'T be Alana's reference frame.  Your own reference
frame moves along with you, and you can't move in it, even
if your name is Alana.

If Alana is the reference frame, and she throws the tennis ball
at 11 km/hr, then the speed of the ball is 11 km/hr in Alana's
reference frame.  Her reference frame moves with  her, so
it makes no difference how fast she is skateboarding in any
other reference frame, who she throws the ball at, or whether
or not he sees it coming and catches it.

Yes, this stuff can get confusing.  And if you think it's bad now,
wait till you start reading some of Prof. Einstein's stuff, where
two people in the same reference frame can watch the same
tennis ball, and not even agree on how fast it's moving, because
THEY're both moving and their own motion makes their rulers
and clocks change !  So they measure different speeds, and
they're both right !

But I got distracted.  I'm sorry.  The point I'm trying to make,
right now when you're just starting to learn reference frames,
is that EVERY time you say a speed, you have to tell which
reference frame the speed is in.  Because, as you're starting
to learn, the same object can have a different speed in every
reference frame.

And, just in case you're thinking about this later today
and you want to ask "Which one is the REAL speed  ?" . . .
THAT's the whole point of learning about reference frames !
There is NO SUCH THING as REAL speed.  It ALWAYS
depends on which reference frame it's measured in.  They're
all different, they're all real, and they're all correct.

makvit [3.9K]3 years ago
3 0

The first thing we must do for this case is to define a frame of reference.

We know that, the frame of reference for this case is Alana.

Therefore, the tennis ball has a speed relative to Alana.

The speed relative to Alana, is the same speed with which Alana throws the tennis ball.

Therefore, the speed of the tennis ball is:

v = 11 Km/h

Answer:

The speed of the tennis ball is:

v = 11 Km/h

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Gwar [14]
The third one.

The nucleus of an atom is made up of protons and neutrons. Protons and neutrons have the same relative mass (rounded to 1). Electrons have an extremely small mass.

Therefore, the particles in the nucleus are more massive than those in the electron cloud.
4 0
2 years ago
A laser beam from Earth is reflected by a mirror placed on the Moon. If the speed of the beam is 3.00 x 108 m / s and the distan
Olin [163]

Answer:

1.27seconds

Explanation:

Speed = 324 m/s , Distance = 411.48m

Time = Distance/Speed

Time = 411.48/324 seconds

Time = 1.27seconds ( Ans)

3 0
3 years ago
What is your average velocity after going 15 meters east followed by 20 meters
adelina 88 [10]

Answer:

0.5 m/s

Explanation:

Velocity = displacement/time taken

going 15 meters east and then 20 meters west gives a displacement of 5 meters.

Velocity v = 5/10

= 0.5 m/s

7 0
3 years ago
A Blu-ray disc is approximately 11 centimeters in diameter. The drive motor of a Blu-ray player is able to rotate up to 10,000 r
stepladder [879]

Answer:

the maximum angular speed (in radians per second) of a Blu-ray disc as it rotates is 57.6 m/s

Explanation:

Given information:

diameter of the disc, d  = 11 cm, r = 5.5 cm = 0.055 m

angular speed ω = 10000 rev/min = (10000 rev/min)(2π rad/rev)(1/60 min/s)

                             = 1000π/3 rad/s

to calculate the maximum angular speed we can use the following formula

ω = v/r

v = ωr

  = (1000π/3)(0.055)

  = 57.6 m/s

8 0
3 years ago
A barometer reads 780 mm Hg. Mercury has a density of 1.36 x 10^4 kg /m^3.
iris [78.8K]

The pressure of the atmosphere, when a barometer reads 780 mm Hg.    Mercury which a density of 1.36 x 10^4 kg /m^3 is B 1.1 x 10^5 N/m^2

This problem can be solved using the formula below

P = dgh................. Equation 1

Where P = Pressure of the atmosphere, d = density of the mercury, h = height of the mercury, g = acceleration due to gravity.

From the question,

Given: d = 1.36×10⁴ kg/m³, h = 780 mm = 0.78 m,

Constant: g = 10 m/s²

Substitute these values into equation 1

P = (1.36×10⁴)(10)(0.78)

P = 10.608×10⁴ N/m²

P ≈ 1.1×10⁵ N/m²

Hence the right answer is B. 1.1×10⁵ N/m²

Learn more about Pressure here: brainly.com/question/23603188

7 0
3 years ago
Read 2 more answers
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