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2 years ago

A simple pendulum has length of 820mm. Calculate the frequency (g = 9.8 ms -2)

Physics

1 answer:

Vadim26 [7]2 years ago

7 0

Answer:

$\huge\boxed{\sf f=0.55 \ Hz}$

Explanation:

Given Data:

Length = l = 820 mm = 0.82 m

Acceleration due to gravity = g = 9.8 ms⁻²

Required:

Frequency = f = ?

Formula:

$\displaystyle f =\frac{1}{2 \pi} \sqrt{\frac{g}{l} }$

Solution:

$\displaystyle f =\frac{1}{2 \pi} \sqrt{\frac{g}{l} } \\\\Put\ the\ givens\\\\f=\frac{1}{2 \pi} \sqrt{\frac{9.8}{0.82} }\\\\ f = 0.159 \times \sqrt{11.95} \\\\f=0.159 \times 3.457\\\\f=0.55 \ Hz\\\\\rule[225]{225}{2}$

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1 year ago

g You drop a 3.6-kg ball from a height of 3.5 m above one end of a uniform bar that pivots at its center. The bar has mass 9.9 k

Salsk061 [2.6K]

Answer:

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Explanation:

First, we will calculate the final speed of the ball when it collides with a seesaw. Using the third equation of motion:

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where,

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Now, we will apply the law of conservation of momentum:

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where,

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m₂ = mass of ball on the other end = 3.6 kg

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Therefore,

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$2gh = v_f^2 - v_i^2\\$

where,

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h = height = ?

vf = final speed = 0 m/s

vi = initial speed = 8.3 m/s

Therefore,

$(2)(9.81\ m/s^2)h = (0\ m/s)^2-(8.3\ m/s)^2\\$

h = 3.5 m

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Answer:

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weqwewe [10]

Answer:

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2 years ago

A simple pendulum has length of 820mm. Calculate the frequency (g = 9.8 ms -2)​

A simple pendulum has length of 820mm. Calculate the frequency (g = 9.8 ms -2)