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2 years ago

A simple pendulum has length of 820mm. Calculate the frequency (g = 9.8 ms -2)

Physics

1 answer:

Vadim26 [7]2 years ago

7 0

Answer:

$\huge\boxed{\sf f=0.55 \ Hz}$

Explanation:

Given Data:

Length = l = 820 mm = 0.82 m

Acceleration due to gravity = g = 9.8 ms⁻²

Required:

Frequency = f = ?

Formula:

$\displaystyle f =\frac{1}{2 \pi} \sqrt{\frac{g}{l} }$

Solution:

$\displaystyle f =\frac{1}{2 \pi} \sqrt{\frac{g}{l} } \\\\Put\ the\ givens\\\\f=\frac{1}{2 \pi} \sqrt{\frac{9.8}{0.82} }\\\\ f = 0.159 \times \sqrt{11.95} \\\\f=0.159 \times 3.457\\\\f=0.55 \ Hz\\\\\rule[225]{225}{2}$

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The described situation is as follows:

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$V_{f}$ Is the final velocity of the object

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b) Begining with (1):

$V_{f}=0+at$ (3)

$V_{f}=at=(9.8 m/s^{2})(1.2 s)$ (4)

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$(11.76 m/s)^{2}=0+2(9.8 m/s^{2})d$ (6)

Clearing $d$ :

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3 years ago

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A simple pendulum has length of 820mm. Calculate the frequency (g = 9.8 ms -2)​

A simple pendulum has length of 820mm. Calculate the frequency (g = 9.8 ms -2)