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Leno4ka [110]
3 years ago
15

1. Find the probability of this set of independent events. rolling a six on the first roll of a 1-6 number cube and rolling an o

dd number on the second roll of the same cube
2. Find the probability of this set of independent events.
drawing a 1, 2, or 3 from 9 cards numbered 1-9, replacing the card, and drawing a 7, 8, or 9
3. A bag contains 3 blue marbles and 2 green marbles. What is the probability of drawing a blue marble followed by a green marble, without replacing the first marble before drawing the second marble?
Mathematics
1 answer:
jeyben [28]3 years ago
7 0
For the first question, the chance of rolling a six is a 1/6 chance because there is one six and six different sides that could be rolled. As a percent, it would be 16.6 %. The probability of rolling an odd number on the second roll would be a 3/6 chance, which as a percent is 50 %. For the second question, both probabilities are 33 % because in both instances you are drawing three cards from nine total, so it would be 3/9. For the third question, the probability of drawing a blue marble is 3/5, because there are three blue marbles and five total marbles. As a percent, this is 60 %. Following this up with a green marble would be 2/4, because there are now 2 green marbles and four total marbles. One of the marbles was not replaced, so we have one less marble. 2/4 as a percent  is 50%.
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For 1.999 × 2.4, how many decimal hops would you move (right to left) to place in your answer?
natali 33 [55]

Answer: 4

Step-by-step explanation: it is 4 because there are a total of 4 different decimal places in the equation so if the equation was 1.2 times 1.2 you would decimal hop 2 times because there are to numbers behind the decimal

5 0
3 years ago
Read 2 more answers
Jasmine has a hair ribbon collection. She ha 33 pink ribbon which is 25% of her collection. How many ribbon are in jasmines coll
jok3333 [9.3K]

Answer:

132 ribbons

Step-by-step explanation:

33/1 = 1/4

33 × 4 = 132

3 0
3 years ago
Find the next 3 terms in the geometric sequence -36, 6, -1, 1/6, ...
timama [110]

we are given

geometric sequence -36, 6, -1, 1/6, ...

first term is -36

a_1=-36

now, we can find common ratio

r=\frac{6}{-36}

r=-\frac{1}{6}

now, we can find nth term

a_n=a_1(r)^{n-1}

now, we can plug values

and we get

a_n=36(-\frac{1}{6})^{n-1}

now, we can find 5th term , 6th term, 7th term

fifth term:

a_5=36(-\frac{1}{6})^{4}

a_5=\frac{1}{36}

sixth term:

a_6=36(-\frac{1}{6})^{5}

a_6=-\frac{1}{216}

seventh term:

a_7=36(-\frac{1}{6})^{6}

a_7=\frac{1}{1296}

so, next terms are

a_5=\frac{1}{36} , a_6=-\frac{1}{216}

, a_7=\frac{1}{1296}.............Answer

6 0
3 years ago
Graph the data below and then answer the questions that follow. year 1=$20,000, year 2=$21,750, year 3=$23,500, year 4=$25,250,
Mariana [72]

Answer:

Since the difference between the value for each year is constant, this is an arithmetic sequence.

Step-by-step explanation:

Year 2 - Year 1 = 21,750 - 20,000 = 1,750

Year 3 - Year 2 = 23,500 - 21,750 = 1,750

Year 4 - Year 3 = Year 5 - Year 4 = 1,750

3 0
3 years ago
Identify the glide reflection rule in the given figure
Maslowich

Answer:

Option (3)

Step-by-step explanation:

Glide reflection of a figure is defined by the translation and reflection across a line.

To understand the glide rule in the figure attached we will take a point A.

Coordinates of the points A and A' are (2, -1) and (-2, 4).

Translation of pint A by 5 units upwards,

Rule to be followed,

A(x, y) → A"[x, (y + 5)]

A(2, -1) → A"(2, 4)

Followed by the reflection across y-axis,

Rule to be followed,

A"(x, y) → A'(-x, y)

A"(2, 4) → A'(-2, 4)

Therefore, by combining these rules in this glide reflections of point A we get the coordinates of the point point A'.

Option (3) will be the answer.

4 0
3 years ago
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