an object that is 8 cm tall is located 2.5 m in front of a plane mirror. The image formed by the mirror appears to be. Find di a
1 answer:
The image is at 2.5 m behind the mirror (virtual image)
Explanation:
We can solve the problem by using the mirror equation:
where
f is the focal length of the mirror
is the distance between the object and the mirror
is the distance between the image and the mirror
For a plane mirror, the focal length is infinite:
And in this problem, the distance of the object from the mirror is
Substituting and solving for , we find the location of the image:
And the negative sign means that the image is located behind the mirror, so it is virtual.
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Answer:
The potential difference between the plates increases
Explanation:
As we know that the capacitance of the capacitor is given by:
(1)
where
q = charge
C = capacitance
V = Voltage or Potential Difference
Also, the capacitance of a parallel plate capacitor is given as:
(2)
where
A = Area of the plates
D = Separation distance between the plates
Now, from eqn (1) and (2):
Now, from the above eqn we can say that:
Potential difference depends directly on the separation distance between the plates of the capacitor and is inversely dependent on the area of the plates of the capacitor.
Therefore, after disconnecting, if the separation between the plates is increased the potential difference across it also increases.
Answer:
Width of sound beam is 7.557 m
Explanation:
First we will calculate the wave length from given data:
λ=v/f
Were:
v is the speed
f is the frequency
We considered the opening long and narrow, Using single slit diffraction formula:
mλ=dsinΘ
where:
d is the crack width
m is the order
Θ is angle
Considering m=1, The angle between first minimum from center of beam is:
The width of beam is:
tanΘ=y/L
Width=7.557 m