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AlladinOne [14]
3 years ago
15

an object that is 8 cm tall is located 2.5 m in front of a plane mirror. The image formed by the mirror appears to be. Find di a

nd whether behind or in front of mirror​
Physics
1 answer:
UkoKoshka [18]3 years ago
6 0

The image is at 2.5 m behind the mirror (virtual image)

Explanation:

We can solve the problem by using the mirror equation:

\frac{1}{f}=\frac{1}{d_o}+\frac{1}{d_i}

where

f is the focal length of the mirror

d_o is the distance between the object and the mirror

d_i is the distance between the image and the mirror

For a plane mirror, the focal length is infinite:

f=\infty

And in this problem, the distance of the object from the mirror is

d_o = 2.5 m

Substituting and solving for d_i, we find the location of the image:

0=\frac{1}{d_o}+\frac{1}{d_i}\\d_i = -d_o = -2.5 m

And the negative sign means that the image is located behind the mirror, so it is virtual.

Learn more about reflection and refraction:

brainly.com/question/3183125

brainly.com/question/12370040

#LearnwithBrainly

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Answer:

<em>The final velocity is 20 m/s.</em>

Explanation:

<u>Constant Acceleration Motion</u>

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

Being a the constant acceleration, vo the initial speed, and t the time, the final speed can be calculated as follows:

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The provided data is: vo=10 m/s, a=5\ m/s^2, t=2 s. The final velocity is:

v_f=10~m/s+5\ m/s^2\cdot 2\ s

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A golf ball is struck with a five iron on level ground. it lands 100.0 m away 4.60 s later. what was the magnitude and direction
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consider the motion in x-direction

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consider the motion along y-direction

v_{oy} = initial velocity in y-direction = ?

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a_{y} = acceleration along x-direction = - 9.8 m/s²

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