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timofeeve [1]
2 years ago
10

A power supply is connected to a 59 Ohm resistor and a 53 Ohm resistor in series. The total current is found to be 0.15 A. What

is the voltage drop across the 53 Ohm resistor? Round your answer to 2 decimal places.
Answer:
Physics
1 answer:
kirill [66]2 years ago
4 0

the answer is 47265.dug

Explanation:

im bot sure

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Help quick physics area question
zlopas [31]

Answer: The area of brick in contact with the floor is 1539 cm^{3}.

Explanation:

Given: Length = 19 cm

Width = 9 cm

Height = 9 cm

As the brick is rectangular in shape. Hence, its area will be calculated as follows.

Area = length \times width  \times height

Substitute the values into above formula as follows.

Area = length \times width  \times height\\= 19 cm \times 9 cm \times 9 cm\\= 1539 cm^{3}

Thus, we can conclude that area of brick in contact with the floor is 1539 cm^{3}.

8 0
2 years ago
What is the correct answer?
damaskus [11]

Answer:

96 million of dollars

Explanation:

p=-6x^3+72x

p=-6(2)^3+72(2)

p=-6(8)+144

p=-48+144

p=96

8 0
2 years ago
What are the positive impacts of Genetically Modified Crops?
xeze [42]

Answer:

The crops will have the ability to be resistant to certain diseases

7 0
2 years ago
Read 2 more answers
A soccer ball is kicked horizontally and rolled off of a 30 meter high cliff. The soccer ball was kicked with a velocity of 17m/
Montano1993 [528]

Answer:

i am doing this rn

Explanation:

COMMENTS

8 0
2 years ago
One end of an insulated metal rod is maintained at 100 ∘C and the other end is maintained at 0.00 ∘C by an ice–water mixture. Th
lozanna [386]

Answer:

k=105.0359\times 10^4\,W.m^{-1}.K^{-1}

Explanation:

Given:

temperature at the hotter end, T_H=100^{\circ}C

temperature at the cooler end, T_C=0^{\circ}C

length of rod through which the heat travels, dx=0.7\,m

cross-sectional area of rod, A=1.1\times 10^{-4}\,cm^2

mass of ice melted at zero degree Celsius, m=8.7\times 10^{-3}\,kg

time taken for the melting of ice, t=15\times60=900\,s

thermal conductivity k=?

By Fourier's Law of conduction we have:

\dot{Q}=k.A.\frac{dT}{dx}......................................(1)

where:

\dot{Q}=rate of heat transfer

dT= temperature difference across the length dx

Now, we need the total heat transfer according to the condition:

we know the latent heat of fusion of ice,  L = 334000\,J.kg^{-1}

Q=m.L

Q=8.7\times 10^{-3}\times 334000

Q=2905.8\,J

Now the heat rate:

\dot{Q}=\frac{Q}{t}

\dot{Q}=\frac{2905.8}{900}

\dot{Q}=3.2287\,W

Now using eq,(1)

3.2287=k\times 1.1\times 10^{-4} \times \frac{100}{0.7}

k=205.4606\,W.m^{-1}.K^{-1}

8 0
3 years ago
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