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4 years ago

6

In order for a length of copper wire or a loop of copper wire to have a magnetic field, what must they have flowing through them

?

1 answer:

Nataliya [291]4 years ago

6 0

Electricity.
When electricity flows through wire (such as a battery circuit) it creates a magnetic field around the wire.

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An undersea research chamber is spherical with an external diameter of 4.70 m . The mass of the chamber, when occupied, is 54300

Ira Lisetskai [31]

Answer: a) 557.3kN b) 543kN

Explanation:

Buoyant force = weight of water displaced.

Formula for buoyant force = mg×(density of fluid/density of object)

Density of fluid = density of sea water = 1025kg/m³

Mass of the chamber(m) = 54300kg

g = acceleration due to gravity = 10m/s²

Density of chamber = mass/volume

Where volume of sphere = 4/3Πr³

radius = 4.70/2 = 2.35m

Volume = 4/3×Π(2.35)³

Volume = 54.37m³

Density of chamber = 54300/54.37

= 998.7kg/m³

Substituting the values into the formula for buoyant force

Buoyant force= 54300×10×{1025/998.7}

= 557299N

= 557.3kN

b) Tension in the cable = mass of cable × acceleration due to gravity

= 54300×10 = 543000N or 543kN.

7 0

3 years ago

Jaime lifts a package weighing 75N. if she lifts it 1.2 m, what work has she done

9966 [12]

Answer:
90 J
Explanation:
W=fd
W=(75)(1.2)
W= 90 J

6 0

3 years ago

The friends are ready to try a problem. A battery has an emf of 12.0 V and an internal resistance of 0.05 Ω. Its terminals are c

Zanzabum

Answer:

Terminal voltage = 11.5 V

Power across load = 119.7 W

Power across internal resistance = 5.4 W

Power delivered by battery = 125.2 W

Explanation:

The current in the circuit is given by

$I=\dfrac{E}{R+r}$

where E is the emf of the battery, R us the load resistance and r is the internal resistance.

$I=\dfrac{12}{1.1+0.05} = 10.43 \text{ A}$

The terminal voltage is the potential difference across the load resistor.

V = I × R = 10.43 A × 1.1 Ω = 11.5 V

The power across any resistance is given by $I^2R$

For the load resistor,

$P_L=10.43^2\times1.1 = 119.7 \text{ W}$

For the internal resistance,

$P_r=10.43^2\times0.05= 5.4\text{ W}$

The power delivered by the battery is

$P = P_L + P_r = 119.7 + 5.4 = 124.1 \text{ W}$

This could also be found by

$P = IE = 10.34\times12 = 125.2 \text{ W}$

The discrepancy in both answers is due to the approximations. The second answer is better.

4 0

4 years ago

Edward runs with a speed of 3m/s. How long would it take him to run 2km? Give your answer in seconds to four significant figures

Whitepunk [10]

Answer:

666.6 seconds

Explanation:

if he runs at 3m/sec he will achieve the goal of 2000m in 666.6 seconds. just divide - 3/2000.

note we have changed 2km to 2000metres

5 0

3 years ago

Your friend won the race that you were both running. Instead of being gracious, your friend made fun of you for losing, and now

nika2105 [10]

Negative peer influence

7 0

3 years ago

Read 2 more answers