Multiply the quantity in ounces (including the unit) by the fraction
(1 pint) / (16 fl oz) .
PART1:
First Combination:
Pizza ($7) + Chicken Strips ($6) + Biscuits ($3) + Grapes ($4) = $20
Second Combination:
Dog Food ($13) + Bread ($3) + Crackers ($2) + Broccoli ($2) = $20
Third Combination:
Shampoo ($4) + Tissues ($3) + Pizza ($7) + Eggs ($3) + Biscuits ($3) = $20
PART 2:
First Combination:
$7.20 + $5.70 + $2.90 + $3.70 = $19.60
No, I wouldn’t have gone over the limit
Second Combination:
$13.40 + $3.50 + $2.00 + $1.90 = $20.80
Yes, I would have gone over the limit
Third Combination:
$3.50 + $2.60 + $7.20 + $2.50 + $2.90 = $18.70
No, I wouldn’t have gone over the limit
Hope this helps!!
Answer:
Step-by-step explanation:
Whitxh answer are u tryna get?
Answer: 11 square root 57
Step-by-step explanation:
Answer:
Step-by-step explanation:
1). Step 4:
![x=\sqrt[3]{5^4}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B5%5E4%7D)
[Since, ![a^{\frac{1}{3}}=\sqrt[3]{a}](https://tex.z-dn.net/?f=a%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7Ba%7D)
]
![x=\sqrt[3]{5\times 5\times 5\times 5}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B5%5Ctimes%205%5Ctimes%205%5Ctimes%205%7D)
Step 5:
![x=\sqrt[3]{(5)^3\times 5}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B%285%29%5E3%5Ctimes%205%7D)
![x=\sqrt[3]{5^3}\times \sqrt[3]{5}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B5%5E3%7D%5Ctimes%20%5Csqrt%5B3%5D%7B5%7D)
2). He simplified the expression by removing exponents from the given expression.
3). Let the radical equation is,
Step 1:
Step 2:
Step 3:
Step 4:
4). By substituting in the original equation.
There is no extraneous solution.
