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garik1379 [7]
3 years ago
7

1. Write the interval shown on the number line

Mathematics
1 answer:
shusha [124]3 years ago
3 0

Answer:

x\geq 5

\{x\  |\  x \geq 5\}   OR {5, 6, 7, 8, .....}

Step-by-step explanation:

First of all, let us have a look at the interval shown on the number line and try to understand it properly.

The number line shows positive numbers starting from 3 that means numbers indicated will be positive numbers.

The number highlighted starts from 5 and there is filled circle at 5.

So, 5 is included in the interval.

The arrow is from 5 towards 8 and so on..

That means Numbers greater than or equal to 5 are represented by the interval.

So, writing as an inequality

Let x represents one of the numbers.

Hence, inequality can be written as:

x\geq 5

Using the set notation:

\{x\  |\  x \geq 5\}

OR

{5, 6, 7, 8, .....}

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Find the ratio in which the lines segment joining A(1,-5) & B(-4,5) is divided by the x-axis. Also find the corrdinates of t
ioda

Step-by-step explanation:

\large\underline{\sf{Solution-}}

<u>Given that </u>

A line segment AB having coordinates of A as (1, - 5) and coordinates of B as (- 4, 5).

Let assume that x - axis divides the line segment joining the points A (1, - 5) and B (- 4, 5) in the ratio k : 1 at C.

Let assume that coordinates of C be (x, 0).

We know,

Section formula :-

Let P(x₁, y₁) and Q(x₂, y₂) be two points in the coordinate plane and R(x, y) be the point which divides PQ internally in the ratio m₁ : m₂. Then, the coordinates of R will be:

\sf\implies \boxed{\tt{ R = \bigg(\dfrac{m_{1}x_{2}+m_{2}x_{1}}{m_{1}+m_{2}}, \dfrac{m_{1}y_{2}+m_{2}y_{1}}{m_{1}+m_{2}}\bigg)}}

So, on substituting the values, we get

\rm \longmapsto\:(x,0) = \bigg(\dfrac{ - 4k + 1}{k + 1}, \:  \dfrac{5k - 5}{k + 1} \bigg)

On comparing y - coordinate on both sides, we get

\rm \longmapsto\:\dfrac{5k - 5}{k + 1}  = 0

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\rm \longmapsto\:5k = 5

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<u>Hence, </u>

The x - axis divides the line segment joining the points A (1, - 5) and B (- 4, 5) in the ratio 1 : 1 at C.

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\rm \longmapsto\:x = \dfrac{ - 4k + 1}{k + 1}

On substituting the value of k, we get

\rm \longmapsto\:x = \dfrac{ - 4+ 1}{1 + 1}

\rm \longmapsto\:x  \: =  -  \: \dfrac{3}{2}

<u>Hence, </u>

The coordinates of point of intersection, C is

\rm\implies \:\boxed{\tt{ Coordinates \: of \: C = \bigg( - \dfrac{3}{2}, \: 0 \bigg) }}

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