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lara [203]
3 years ago
9

3.10354 as a fraction

Mathematics
1 answer:
BARSIC [14]3 years ago
5 0
The simplified fraction is 3 1/10 The exact answer is 3 10354/100000
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Helpppppp. Pleaseeeeeeeeeeee
Irina-Kira [14]
I think it’s 0.85d, but i’m not sure
7 0
3 years ago
Bargains r us store offers a 12 roll package of wipey wonder toilet paper for $2.59.The 6 roll package is on sale for $1.25.Whic
lawyer [7]
$1.25 because if you bought 2 packs of them it would be $2.50 so you would be 0.09 cheaper
3 0
3 years ago
Help please ! thank u
KonstantinChe [14]

Given:

In triangle ABC,m\angle A=138^\circ,c=19,a=29.

To find:

The m\angle C.

Solution:

According to the law of sines:

\dfrac{\sin A}{a}=\dfrac{\sin B}{b}=\dfrac{\sin C}{c}

Taking \dfrac{\sin A}{a}=\dfrac{\sin C}{c}, we get

\dfrac{\sin 138^\circ}{29}=\dfrac{\sin C}{19}

\dfrac{0.66913}{29}\times 19=\sin C

0.4383959=\sin C

Taking sin inverse on both sides, we get

\sin{-1}0.4383959=C

26.001577^\circ=C

C\approx 26^\circ

Therefore, the correct option is b.

6 0
3 years ago
The area of the triangle shown is represented by A= square root of s(s-10)(s-7)(s-5), where s is equal to half the perimeter. Wh
dezoksy [38]
It should be 3.25
S is half the perimeter, so .5*(7+5+10)=11
Plug in 11 and you get A=sqrt(264)
A also is half base times height
sqrt(264)=.5*10*h
h=sqrt(264)/5
h=3.25
4 0
3 years ago
In a lab experiment, 610 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to dou
Alex777 [14]

Answer:

It would take 19 hours and 36 minutes until there are 1040 bacteria present.

Step-by-step explanation:

Given that in a lab experiment, 610 bacteria are placed in a petri dish, and the conditions are such that the number of bacteria is able to double every 23 hours, to determine how long would it be, to the nearest tenth of an hour, until there are 1040 bacteria present, the following calculation must be performed:

610X = 1040

X = 1040/610

X = 1.7049

2 = 23

1.7049 = X

1.7049 x 23/2 = X

39.2131 / 2 = X

19.6 = X

100 = 60

60 = X

60 x 60/100 = X

36 = X

Therefore, it would take 19 hours and 36 minutes until there are 1040 bacteria present.

5 0
2 years ago
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