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3 years ago

You were assigned 20 practice problems. You completed 5 problems. What fraction of the assigned problems do you have left?

Mathematics

2 answers:

Anna11 [10]3 years ago

4 0

3/4

please

Elena L [17]3 years ago

3 0

3/4 is the answer.

Step-by-step explanation:

20-5=15

15/20=3/4

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In many cases the Law of Sines works perfectly well and returns the correct missing values in a non-right triangle. However, in

Agata [3.3K]

$\frac{\sin B}{b}=\frac{\sin A}{a} \\ \\ \sin B=\frac{b \sin A}{a} \\ \\ \sin B=\frac{13 \sin 29^{\circ}}{7.2} \\ \\ \boxed{m\angle B =\arcsin \left(\frac{65\sin 29^{\circ}{36} \right), 180^{\circ}-\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right)}$

Considering the diagram. $\angle B$ is shown to be acute, so $\boxed{m\angle B=\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right)}$ .

Angles in a triangle add to 180°, so $m\angle C= 151^{\circ}-\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right)$ .

Using the law of cosines,

$AB=\sqrt{13^2 + 7.2^2-2(13)(7.2)\cos \left(\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right) \right)} \\ \\ \boxed{AB=\sqrt{220.84-187.2\cos \left(\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right) \right)}}$

3 0

1 year ago

An unbalanced die is manufactured so that there is a 20% chance of rolling a “six." The die is rolled 6

SIZIF [17.4K]

Answer:

Probability of rolling at least 4 sixes is 0.01696.

Step-by-step explanation:

We are given that an unbalanced die is manufactured so that there is a 20% chance of rolling a “six." The die is rolled 6 times.

The above situation can be represented through binomial distribution;

$P(X = r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r};x=0,1,2,3,.......$

where, n = number trials (samples) taken = 6 trials

r = number of success = at least 4

p = probability of success which in our question is probability of

rolling a “six", i.e; p = 0.20

Let X = Number of sixes on a die

So, X ~ Binom(n = 6, p = 0.20)

Now, Probability of rolling at least 4 sixes is given by = P(X $\geq$ 4)

P(X $\geq$ 4) = P(X = 4) + P(X = 5) + P(X = 6)

= $\binom{6}{4} \times 0.20^{4} \times (1-0.20)^{6-4}+\binom{6}{5} \times 0.20^{5} \times (1-0.20)^{6-5}+\binom{6}{6} \times 0.20^{6} \times (1-0.20)^{6-6}$

= $15 \times 0.20^{4} \times 0.80^{2}+6 \times 0.20^{5} \times 0.80^{1}+1 \times 0.20^{6} \times 0.80^{0}$

= 0.0154 + 0.00154 + 0.000064

= 0.01696

Therefore, probability of rolling at least 4 sixes is 0.01696.

8 0

3 years ago

Help me find the slope please guys Im struggling

tatuchka [14]

Answer:

negative 1

Step-by-step explanation:

$\frac{y2 - y1}{x2 - x1} = m$

the 2 points: (-2,0), (-3,1)

(1-0)/(-3+2)

=-1

m=-1

brainliest please

7 0

3 years ago

Given: F(x) = 2x2+ 1, G(x) = 2x - 1, H(x) = x F(3) + G(4) - 2H(5) = 16 26 34

Roman55 [17]

Answer:

Step-by-step explanation:

Put the numbers where the variables are and evaluate:

F(3) = 2(3)^2 +1 = 19

G(4) = 2(4) -1 = 7

H(5) = 5

Then the desired sum is ...

F(3) +G(4) -2H(5) = 19 +7 -2(5) = 16

3 0

3 years ago

What is N in -2n+2(3n+14)=-20

seraphim [82]

Answer:

To solve for n you need to get it by itself

First you want to distribute your 2 through the (3n+14)

-2n+6n+28=-20 (2*3n+2*14= 6n+28)

Now you want to combine any like terms if possible

4n+28=-20 (-2n+6n=4n, both like terms)

Then you want to subtract -28 from both sides

4n=-48 (28-28=0, -20-28=-48)

Lastly you want to divide both sides by 4

n=-12 (4n/4=n, -48/4= -12)

4 0

3 years ago