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3 years ago

BRAINLIEST ANSWER TO FIRST ANSWERER What is the value of x?

Mathematics

1 answer:

grigory [225]3 years ago

3 0

It's really simple

if a+95=180 you solve for a

a+95=180
-95 -95
a=85

a triangle in total is 180 degrees

now that you know two of the angles find x is really easy

you add 60+85

you get 145

you then subtract 180-145

and get 35 as the answer

x=35

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Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

ANSWER:

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

SOLUTION:

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

3 years ago

the second term of a geometric sequence is 18 and the fourth term is 8 find the common ratio . And find the sum of the first 6 t

777dan777 [17]

Answer:

ratio: 2/3
sum: 73 8/9

Step-by-step explanation:

The general term of a geometric sequence is ...

an = a1·r^(n-1)

You have the 2nd and 4th terms, so ...

a2 = a1·r^(2-1) = a1·r

a4 = a1·r^(4-1) = a1·r^3

We can find r from the ratio ...

a4/a2 = (a1·r^3)/(a1·r) = r^2 = 8/18 = 4/9

Then r is ...

r = √(4/9) = 2/3 . . . . the common ratio

The first term is ...

a2 = 18 = a1·(2/3)

a1 = (3/2)·18 = 27

The sum of the first 6 terms is ...

Sn = a1·(r^n -1)/(r -1)

S6 = 27·((2/3)^6 -1)/(2/3 -1)

S6 = 27·(64/729-1)/(2/3-1) = (27)(665)/243 = 73 8/9

The sum of the first 6 terms is 73 8/9.

_____

Check on the sum

The first 6 terms are ...

27, 18, 12, 8, 5 1/3, 3 5/9

Their sum is 73 8/9, as above.

8 0

3 years ago

The number 28 please somebody help me...

MArishka [77]

Where is the persons info

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4 years ago

Which is the graph of g(x) = [X + 3]?

Vanyuwa [196]

Answer

D or the fourth one because i took the quiz and got it right

3 0

3 years ago

If h(x) = (f o g)(x) and h(x) = ∛7x+1, find f(x) and g(x)

Mariana [72]

There's more than one way to combine them really
but an obvious one will be

$\bf \begin{array}{llll}
h(x)&=&(f\circ g)(x)\\\\
&&\sqrt[3]{7x+1}\\\\
&&\sqrt[3]{g(x)}\leftarrow 
\begin{array}{llll}
f(x)=\sqrt[3]{x }\\\\
g(x)=7x+1
\end{array}
\end{array}\\\\
-----------------------------\\\\
(f\circ g)(x)\iff f[\quad g(x)\quad ]=\sqrt[3]{g(x)}\implies f[\quad g(x)\quad ]=\sqrt[3]{7x+1}$

7 0

3 years ago