The block's speed at the point where x=0.25A is v = 31.95 cm/s.
<h3>What is Spring constant?</h3>
The spring stiffness is quantified by the spring constant, or k. For various springs and materials, it varies. The stiffer the spring is and the harder it is to stretch, the bigger the spring constant.
question is incomplete, this is the remaining statement
What is the amplitude of the subsequent oscillations? And What is the block's speed at the point where x=0.25A?
x = Asin(wt)
v = Aw coswt
at t = 0
w = sqrt(k/m)
v = Aw
A = v/w
A = 7.17 cm
part b )
E = 1/2mv^2 + 1/2kx^2 = 1/2kA^2
mv^2 + k(1/4A)^2 = 1/2kA^2
mv^2 + kA^2/16 = kA^2
mv^2 = kA^2 - kA^2/16
mv^2 = 15kA^2/16
v^2 = 15/16 * (k/m) * A^2
v^2 = 15/16 *w^2A^2
v = sqrt(15/16) * wA
v = 31.95 cm/s
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Answer:
Tech B
Explanation:
The control of electric actuators may be through through a two-wire or a five-wire circuit through the driver circuit by bidirectionally controlling via the motor wire polarity. The door position is determined by counting the actuator commutator pulses by the control module in the actuator with 2-wire, while the actuator with 5-wire uses potentiometer feedback.
The A/C ECU is the Air Condition Engine Control Unit.
Answer:
9.74 x 10^7 m/s
Explanation:
V = 27000 V
energy of electrons = e x V
K = 1.6 x 10^-19 x 27000 = 43200 x 10^-19 J
Energy = 1/2 m v^2
43200 x 10^-19 = 0.5 x 9.1 x 10^-31 x v^2
v^2 = 9.495 x 10^15
v = 9.74 x 10^7 m/s