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3 years ago

10

20- A gram of distilled water at 4° C:

1 answer:

Usimov [2.4K]3 years ago

6 0

Answer:

D. will decrease slightly in volume when heated to 6° C

Explanation:

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Which court case provided for Judicial Review?

vfiekz [6]

Answer:

The best-known power of the Supreme Court is judicial review, or the ability of the Court to declare a Legislative or Executive act in violation of the Constitution, is not found within the text of the Constitution itself. The Court established this doctrine in the case of Marbury v. Madison (1803).

6 0

3 years ago

A student uses a spring loaded launcher to launch a marble vertically in the air. The mass of the marble is

GarryVolchara [31]

Answer:

Part a)

When spring compressed by 2 cm

H = 1.47 m

Part b)

When spring is compressed by 4 cm

H = 5.94 m

Explanation:

Part a)

As we know that the spring is compressed and released

so here spring potential energy is converted into gravitational potential energy at its maximum height

So we will have

$\frac{1}{2}kx^2 = mg(H + x)$

$0.5(220)(0.02)^2 = 0.003(9.81)(H + 0.02)$

so we have

$H = 1.47 m$

Part b)

Similarly when spring is compressed by 4 cm

then we have

$\frac{1}{2}kx^2 = mg(H + x)$

$0.5(220)(0.04)^2 = 0.003(9.81)(H + 0.04)$

so we have

$H = 5.94 m$

8 0

4 years ago

Can someone please help me! BRAINLIEST ANSWER! What happens after the Gulf Stream travels north?

Irina-Kira [14]

A should be the answer since it makes the water down there cold and the air also. (asked my grandma haha

3 0

3 years ago

Please show all the steps and work. The answer is -3.9 m/s2

konstantin123 [22]

Given that,

Initial velocity of the airplane = 66 m/s

Distance = 560 m

Final velocity of the airplane = 0 (stops)

To find,

Acceleration of the airplane.

Solution,

Let us consider that a is the acceleration of the airplane. We can find it using third equation of motion as follows :

$v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2s}\\\\a=\dfrac{0^2-66^2}{2(560)}\\\\a=-3.9\ m/s^2$

Therefore, the acceleration of the airplane is $-3.9\ m/s^2$

8 0

3 years ago

Scientists aboard the International Space Station are threatened by a 2.8 kg meteor hurtling toward them at 5.4 x 103 m/s. They

frez [133]

Answer:

c) 1.3 X 10⁵ N

Explanation:

<u>Step 1:</u> From equation of motion; V² = U² +2as

where, U and V are initial and final velocity respectively,

a is the acceleration and s is the distance traveled

(5400)² = 0² +2*a*193

a = (5400)²/ (386)

a = 75544.04 m/s²

<u>Step 2:</u> calculate the maximum force applied to the meteor

$F_{max} = m*a$

$F_{max} = 2.8*75544.04$ = 211,523.312 N

<u>Step 3:</u> calculate the average force applied to the meteor

$F_{avg} = \frac{1}{2}F_{max}$

$F_{avg} = \frac{1}{2}(211,523.312 N)$ = 105,761.7 N

$F_{avg} =$ 1.1 X 10⁵ N

The nearest option is C

4 0

3 years ago