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Sav [38]
4 years ago
11

Which of the following is not a force causing plate motion?

Physics
2 answers:
nataly862011 [7]4 years ago
5 0
The answer should be B
jolli1 [7]4 years ago
3 0
B is the answer to this
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Describe the energy of a playground swing at its highest point
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A roller coaster at Cedar point is at the top of the first drop (100 M). the car with all of it’s passengers weighs 1100 KG. wha
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4 years ago
A particle executes linear harmonic motion about the point x = 0. At t = 0, it has displacement x = 0.37 cm and zero velocity. T
lukranit [14]

Answer:

(a) The period is 4s

(b) The angular frequency is pi/2 radians

(c) The amplitude is 0.37cm.

(d) The displacement at time is  (0.37 cm) cos((pi/2)*t)

(e) The Velocity at time t is v = (0.58 cm)(sin((pi/2)*t)

(f) The maximum speed is  v_{m} = -0.58 cm/s

(g) The  maximum acceleration is 0.91 cm/s^2

Explanation:

We have a particle which oscillates with frequency of f = 0.25 Hz about the point x = 0.At t = 0, the displacement of the particle is = 0.37 cm and its velocity is zero.

(a) The period of the oscillations is,

T = 1/f

so

T = 1/(0.25 Hz)

T = 4.0s

(b) The angular frequency is,

f = 2\pi f\\

f = = 2(\pi)(0.25 Hz) =\pi /2  \\ radians

(c) Since

The amplitude is the maximum displacement that the particle makes from the equilibrium point, or when the speed of the particle is zero,

that is

x_{m}= 0.37 cm

(d) The displacement as a function of t is given be,

x = x_{m} cos(ωt+Φ)

as x = x_{m  t = 0, we get cos(Ф) = 1 = 0

so this equation becomes

x= (0.37 cm) cos((pi/2)*t)

(e) Now we need to find the speed of the particle as a function of t

the speed is the derivative of the displacement that is

v = dx/dt = -(0.37)(pi/2)(sin((pi/2)*t)

so the velocity at time t is

 v = (0.58 cm)(sin((pi/2)*t)

(f) Since

v = v_{m} sin(ωt+Ф)

then from part (e) we get

v_{m} = -0.58 cm/s

(g)

The amplitude of the maximum acceleration is

a_{m} = x_{m ω^2

      = (0.37 cm) (pi/2) = 0.91 cm/s^2

this is the maximum acceleration

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3 years ago
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64 meters from the base of the cliff.
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