Help! Help! Anyone! Please!

An opaque bag contains 5 green marbles 3 blue marbles and 2 red marbles. What is the probability of randomly picking out a marbl

anastassius [24]

Answer= .2 probability

Explanation: Since there is a total of 10 marbles, and 2 are red, you would divide the red marbles (2) out of the total marbles (10) which would get u .2. Since it’s asking for probability, we would keep .2 a decimal.

6 0

2 years ago

Integers contain whole numbers True or False

murzikaleks [220]

Answer:

true...integers are whole number...both negative and positive

Step-by-step explanation:

4 0

2 years ago

Which has the least value for 9? *

marishachu [46]

Answer:

0.1039

Step-by-step explanation:

Obtain the place value of 9 in each value and choose the smallest :

1.95

9 is the first digit after the decimal point ; which is equal to 0.9 = tenth place

0.1039

9 is the 4th digit after the decimal point ; which is equal to 0.0009 = ten thousandth place

3.092

9 is the second digit after the decimal point ; which is equal to 0.09 = hundredth place

2.009

9 is the third digit after the decimal point ; which is equal to 0.009 = thousandth place

Hence the smallest value of 9 among the options given resides in 0.1039 (ten thousandth place).

3 0

3 years ago

Solve for (x) x+15=3x+5

dolphi86 [110]

Answer:

$x + 15 = 3x + 5 \\ 15 - 5 = 3x - x \\ 10 = 2x \\ \frac{10}{2} = \frac{2x}{2} \\ x = 5$

hope this helps....

8 0

2 years ago

Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hyp

Hatshy [7]

Answer:

We can assume that the statistic is $z_{calc}=0.78$

$p_v = 2* P(z>0.78) = 0.435$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of interest is not different from 3/5

Step-by-step explanation:

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is equal to 3/5 or not.:

Null hypothesis: $p=3/5$

Alternative hypothesis: $p \neq 3/5$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

We can assume that the statistic is $z_{calc}=0.78$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v = 2* P(z>0.78) = 0.435$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of interest is not different from 3/5

7 0

2 years ago