$1.\:2^x=64, x=\boxed{6},\\2.\:x=\left(\frac{2}{3}\right)^3,x=\boxed{\frac{8}{125}}\\3.\:3\cdot (3^4)=3^x, x=\boxed{5}\\4.\:\frac{16}{25}=x^2,x=\boxed{\frac{4}{5}},$

Step-by-step explanation:

$1.\\\\2^x=64,\\\log 2^x=\log64,\\x\log 2=\log 64,\\x=\frac{\log 64}{\log 2}=\boxed{6}$

$2.\\x=\left(\frac{2}{5}\right)^3=\frac{2^3}{5^3}=\boxed{\frac{8}{125}}$

3. This problem incorporates an exponent property.

Exponent property used: $a^b\cdot a^c=a^{(b+c)}$ , yielding an answer of $\boxed{5}$

$4.\\\\\frac{16}{25}=x^2,\\x=\sqrt{\frac{16}{25}}=\frac{\sqrt{16}}{\sqrt{25}}=\boxed{\frac{4}{5}}$

3 0

3 years ago

Read 2 more answers

140 degrees decreased by 65%

BaLLatris [955]

Hey there!
Here are the steps involved:

1.Change 65% into a decimal. Move the decimal two places to the left and you get 0.65.

2. Multiply 0.65 by 50.
140 x 0.65 = 91.

3. Since you are decreasing 140 by 65%, subtract 140 by 91.
140-91= 49

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7 0

3 years ago

PLZ HELPPPPPPP THE QUESTION IS IN THE PIC

IrinaK [193]

Answer:

Step-by-step explanation:

7 0

2 years ago