Answer:
B. 100 percent white
Explanation:
According to Mendel's law of dominance, the dominant allele of a gene masks the expression of the recessive allele in a heterozygous state. Therefore, when two pure breeding plants that differ with respect to one genetic trait are crossed, the progeny expresses only the dominant phenotype. Here, one allele should be completely dominant over the other. The allele for the white flowers is completely dominant over the allele for the blue flowers.
Let' assume that the allele "W" imparts white color to the flowers while the allele "w" gives blue color. When a true-breeding blue-flowered plant (ww) is crossed with a true-breeding white-flowered plant (WW), the progeny would be heterozygous for the dominant allele "W" and would exhibit "white color of flowers" (the dominant trait).
WW (white-flowered plant) x ww (blue-flowered plant) = Ww (white-flowered plant)
I have no idea, i speak english how about u
Answer: The genotype ratio is 2Ff : 2ff
The phenotype ratio is two normal feathered birds to two silky feathered birds.
Explanation: Let F represent the gene for normal feather and f represent the gene for silky feather. F is dominant while f is recessive, therefore a male that is hybrid for trait of normal feather is heterozygous and will have a genotype of Ff, a female that is homozygous for silky feather will have a genotype of ff.
A cross between Ff and ff will yield 2Ff birds and 2ff birds. Since F is dominant, a bird having genotype of Ff will manifest outwardly as blue feathered birds while ff will manifest outwardly as silky feathered birds because f is recessive and must occur in a homozygous condition in order to manifest phenotypically. Therefore, the genotype ratio is 2Ff: 2ff.
See the punnett square attached for more information
Answer:
transcription of mRNA from DNA
small ribosomal subunit binds to mRNA
initiation complex formed with addition of large ribosomal subunit
translocation
codon recognition (non-initiating site)
peptide bond formation
ribosome reads a stop codon
polypeptide chain is released from the P site
ribosomal subunits dissociate
Explanation:
The above describes the process of translation in the ribosome. After transcription of DNA to mRNA, the mRNA is taken to the ribosome to undergo translation, here the mRNA binds to the small ribosomal subuits and to other initiation factors; binding at the mRNA binding site on the small ribosomal subunit then the Large ribosomal subunits joins in.
Translation begins (codon recognition; initiating site) at the initiation codon AUG on the mRNA with the tRNA bringing its amino acid (methionine in eukaryotes and formyl methionine in prokaryotes) forming complementary base pair between its anticodon and mRNA's AUG start codon. Then translocation occurs with the ribosome moving one codon over on the mRNA thus moving the start codon tRNA from the A site to the P site, then codon recognition occurs (non-initiating site again) which includes incoming tRNA with an anticodon that is complementary to the codon exposed in the A site binds to the mRNA.
Then peptide bond formation occurs between the amino acid carried by the tRNA in the p site and the A site. When the ribosome reads a stop codon, the process stops and the polypeptide chain produced is released and the ribosomal subunits dissociates.
Answer:
Collaborative empiricism
Explanation:
Collaborative empiricism is based on establishing a therapeutic relationship which is becomes a partnership by which the therapist and patient work together as a team to identify maladaptive cognitions and behaviour, test their validity, and make revisions to the therapy if needed.
