A small monster collector has captured ten Bagel-type small monsters. Each Bagel-type small monster has a 35% chance of being a
Sesame Seed-subtype and a 20% chance of being a Whole Wheat-subtype.What is the probability of exactly eight of the captured small monsters being Whole Wheat-subtypes?What is the probability of at least one of the captured small monsters being a Sesame Seed-subtype?What is the probability that there are no Sesame Seed- or Whole Wheat-subtype small monsters captured?What is the probability that are at least two Whole Wheat/Sesame Seed dual-subtype small monsters captured?
1 answer:
Answer:
Check the explanation
Explanation:
Each Bagel-type small monster has 0.35 probability of being a Sesame Seed-subtype and 0.2 probability of being a Whole Wheat-subtype.
The probability that exactly 8 of them are Whole Wheat-subtype is using multiplication principle, because first need to choose which 8 are Whole Wheat-subtype, and if exactly 8 of them are Whole Wheat-subtype, then other two are not Whole Wheat-subtype. The former has probability 0.2, while the latter has probability 1-0.2 = 0.8 .
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Using the knowledge in computational language in JAVA it is possible to write the code being Input a list of employee names and salaries and store them in parallel arrays
<h3>Writting the code in JAVA:</h3>
<em>BEGIN</em>
<em>DECLARE</em>
<em>employeeNames[100] As String</em>
<em>employeeSalaries[100] as float</em>
<em>name as String</em>
<em>salary, totalSalary as float</em>
<em>averageSalary as float</em>
<em>count as integer</em>
<em>x as integer</em>
<em>rangeMin, rangeMax as float</em>
<em />
<em>INITIALIZE</em>
<em>count = 0;</em>
<em>totalSalary =0</em>
<em />
<em />
<em>DISPLAY “Enter employee name. (Enter * to quit.)”</em>
<em>READ name</em>
<em />
<em>//Read Employee data</em>
<em>WHILE name != “*” AND count < 100</em>
<em />
<em>employeeNames [count] = name</em>
<em>DISPLAY“Enter salary for “ + name + “.”</em>
<em>READ salary</em>
<em>employeeSalaries[count] = salary</em>
<em>totalSalary = totalSalary + salary</em>
<em>count = count + 1</em>
<em />
<em>DISPLAY “Enter employee name. (Enter * to quit.)”</em>
<em>READ name</em>
<em />
<em>END WHILE</em>
<em />
<em>//Calculate average salary with mix , max range</em>
<em>averageSalary = totalSalary / count</em>
<em>rangeMin = averageSalary - 5</em>
<em>rangeMax = averageSalary + 5</em>
<em />
<em>DISPLAY “The following employees have a salary within $5,000 of the mean salary of “ + averageSalary + “.”</em>
<em />
<em>For (x = 0; x < count; x++)</em>
<em>IF (employeeSalaries[x] >= rangeMin OR employeeSalaries[x] <= rangeMax )</em>
<em>DISPLAY employeeNames[x] + “\t” + employeeSalaries[x]</em>
<em>END IF</em>
<em>END FOR</em>
<em>END</em>
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